 | Zadock Thompson - Arithmetic - 1832 - 186 pages
...left hand period, and place its root in the quotient. Subtract the cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the quotient by 300, calling it the triple square, and the quotient by 30, calling... | |
 | Catharine Esther Beecher - Arithmetic - 1833 - 296 pages
...greatest cube in the left hand period, and subtract it from that period. Place the root in the quotient, and to the remainder bring down the next period, for a dividend. 3. Square the root already found (understanding a cipher at the right) and multiply it by 3 for a divisor.... | |
 | Daniel Adams - Arithmetic - 1833 - 268 pages
...and write its root as a quotient in division. Subtract the square number.from the left hand period, and to the remainder bring down the next period for a dividend. . III. Double the root already found for a divisor ; seek how many times the divisor is contained in... | |
 | William Templeton (engineer.) - 1833 - 224 pages
...period ; then from the first period subtract the greatest cube it contains ; put the root as a quotient, and to the remainder bring down the next period for a dividend. Find a divisor by multiplying the square of the root by 300 ; see how often it is contained in the... | |
 | Frederick Emerson - Arithmetic - 1834 - 300 pages
...period, and write its root in the quotient. Subtract the square of this root from the left hand period, and to the remainder bring- down the next period for a dividend. Thirdly — Double the root already found, for a divisor. Ascertain how many times the divisor is contained... | |
 | Benjamin Snowden - 1835 - 108 pages
...its root for the first figure of the root sought. 2. — Subtract this cube from the first period, and to the remainder bring down the next period for a dividend. 3. — Find a divisor by multiplying the square of the root by 300. 4. — Divide the dividend by this... | |
 | James L. Connolly (mathematician.) - Arithmetic - 1835 - 264 pages
...left hand, putting the root thereof in the quotient, and the said cube number under the first point, and subtract it therefrom, and to the remainder bring down the next point, and call that the re. solvend. Thirdly, triple the quotient, and place it under the resolvend,... | |
 | George Willson - Arithmetic - 1836 - 202 pages
...of it at the right hand of the given number for the first figure of the root, and the square itself under the period, and subtract it therefrom, and to...a dividend. 3. Double the root already found, and annex a cipher to tho product, for a divisior. Seek how many times this di. visor is contained in the... | |
 | William Ruger - Arithmetic - 1836 - 274 pages
...given number, (after the manner of a. quotient in division,) for the first figure of the root, and the square number, under the period, and subtract it therefrom, and to the remainder bring down. the two figures of the next following period, for a dividend,. Place tvfice the root, already found, on... | |
 | Mathematics - 1836 - 488 pages
...subtract from the highest period the greatest square contained in it, place the root in the quotient, and to the remainder bring down the next period for a dividend. 2. Double the root already found, (understanding a cypher at the right,) for a divisor, and divide... | |
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... subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained... 
