 When a decimal number is to be divided by 10, 100, 1000, &c., remove the decimal point as many places to the left as there are ciphers in the divisor, and if there be not figures enough in the number, prefix ciphers.  The Elements of Arithmetic - Page 76by Augustus De Morgan - 1840 - 166 pagesFull view - About this book
 | William Vogdes - Arithmetic - 1847 - 324 pages
...quotient carried on to any degree of exactness. 4. To divide by 10, 100, 1000 or the like, move the point as many places to the left as there are ciphers in the divisor. The quotient figure is always of the same value with that figure of the dividend, under which... | |
 | Charles Davies - Arithmetic - 1847 - 368 pages
...172. When any decimal number is to be divided by 10, 100, 1000, &c., the division is made by removing the decimal point as many places to the left as there are 0's in the divisor ; and if there be not so many figures on the left of the decimal point, the deficiency... | |
 | John Hunter (of Uxbridge.) - 1847 - 266 pages
...as a divisor, the quotient may be represented by merely shifting the decimal point of the dividend as many places to the left as there are ciphers in the divisor. Thus, 860 -f. 100 = 860-0 -r- 100 = 8-6; 45 -f- 1000 = 45-0 4- 1000 = -045; 23-47 4- 10000... | |
 | James Bates Thomson - Arithmetic - 1847 - 426 pages
...given, the price of one is found by simply removing tlie decimal point in the given cost or dividend, as many places to the left as there are ciphers in the divisor. (Art. 331.) 28. Bought 1000 bricks for $7.20 : what is that apiece ? 29. If 1000 feet of hemlock... | |
 | James Bates Thomson - Arithmetic - 1847 - 434 pages
...given, the price of one is found by simply removing the decimal point in the given cost or dividend, as many places to the left as there are ciphers in the divisor. (Art. 331.) 28. Bought 1000 bricks for $7.20 : what is that apiece? 29. If 1000 feet of hemlock... | |
 | James Bates Thomson - Arithmetic - 1848 - 434 pages
...given, the price of one is found by simply removing the decimal point in the given cost or dividend, as many places to the left as there are ciphers in the divisor. (Art. 331.) 28. Bought 1000 bricks for $7.20 : what is that apiece? 29. If 1000 feet of hemlock... | |
 | George Roberts Perkins - Arithmetic - 1849 - 346 pages
...0-4051. Ans. 2-223 + . •57". We may, obviously, divide any decimal by 10, 100, 1000, &c., by removing the decimal point as many places to the left as there are ciphers in the divisor : when there are not so many figures at the left of the decimal point, we may prefix ciphers.... | |
 | George Roberts Perkins - Arithmetic - 1850 - 364 pages
...by 0-4051. Ans. 2-223+. 57. We may, obviously, divide any decimal by 10, 100, 1000, &c., by removing the decimal point as many places to the left as there are ciphers in the divisor ; when there are not so many figures at the left of the decimal point, we may prefix ciphers.... | |
 | Charles Davies - Arithmetic - 1850 - 412 pages
...1.—When any decimal number is to be divided by 10, 100, 1000, &c., the division is made by removing the decimal point as many places to the left as there are O's in the divisor ; and if there be not so many figures on the left of the decimal point, the deficiency... | |
 | Calvin Tracy - 1851 - 214 pages
...+, implying more. (See 4th sum.) § 90, — To divide a decimal by 10, 100, 1000, &c. RULE. Remove the decimal point as many places to the left as there are ciphers in the divisor. 1. Divide 30515.50 by 100. Ans. 305.1550. 2. Divide 36.5 by 10. Ans. 3.65. 3. Divide 36.10... | |
| |
