 | Correspondence schools and courses - 1909 - 886 pages
...since, pointing off the periods, we get 83'74'08'01, or four periods; consequently, there must be four figures in the root. In like manner, the square root of 50,625 must contain three figures, since there are (5'06'25) three periods. The extreme left-hand period may contain either... | |
 | James A. Lyons - Business mathematics - 1912 - 392 pages
...can never exceed six figures, etc. Hence if we point off the power into periods of three figures each the number of periods will indicate the number of figures in the root. 1. Find the cube root of 91125 cu. in. SOLUTION 91'125|45 64 — 5425 480027125 600 25 27125 EXPLANA... | |
 | Earle Bertram Norris, Kenneth Gardner Smith, Ralph Thurman Craigo - Arithmetic - 1912 - 208 pages
...each way. p=l 102=1'00 1002 = 1'00'00 From these it is evident that the number of periods indicates the number of figures in the root. Thus the square root of 103684 contains 3 figures because this number (10'36'84) contains three periods. Also the square root... | |
 | Earle Bertram Norris, Kenneth Gardner Smith, Ralph Thurman Craigo - Arithmetic - 1912 - 210 pages
...each way. p = l 102=1'00 1002 = 1'00'00 From these it is evident that the number of periods indicates the number of figures in the root. Thus the square root of 103684 contains 3 figures because this number (10'36'84) contains three periods. Also the square root... | |
 | United States. Bureau of Naval Personnel - Arithmetic - 1913 - 144 pages
...root. This is done by pointing off the number into periods of two figures each, beginning at the right. The number of periods will indicate the number of...root. Thus, the square root of 83,740,801 must contain four figures, since, pointing off the periods, we get 83'74'08'01, or four periods; consequently, there... | |
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In order to find the square root of a number, the first step is to find how many figures there will be in the root. This is done by pointing off the number into periods of two figures each, beginning at the rig/it. 
