 | Shelton Palmer Sanford - Arithmetic - 1872 - 404 pages
...are 56, 72 and 84 feet ? Ant. 221.23 sq. yd. ART. 361. To FIND THE AREA OF A TRAPEZOID. Multiply half the sum of the parallel sides by the perpendicular distance between them. 1. The parallel sides of a trapezoid are 36 and 24 feet, and its breadth 16 feet ; what is the area... | |
 | Lorenzo Fairbanks - 1875 - 472 pages
...The part broken off was 20 feet long: what was the length of the pole ? Ans. 36 feet. PROBLEM V. 712. To find the area of a trapezoid. • RULE. — Multiply the sum of the parallel sides by the altitude, and take half the product. EXAMPLES. 1. Required the area of the trapezoid ABCD, whose parallel... | |
 | Henry Lewis (M.A.) - Measurement - 1875 - 104 pages
...four-sided figure having two opposite sides parallel. To find the area of a trapezoid multiply half the sum of the parallel sides by the perpendicular distance between them. The reasonableness of this rule may be demonstrated without any strictly mathematical investigation,... | |
 | Thomas Hunter - Geometry, Plane - 1878 - 142 pages
...it 28 and 33J feet. Ans. 222^ yards. PROBLEM VT. To find the area of a trapezoid. RULE.—Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area.* 1. The parallel sides of a trapezoid are 750 and 1225, and the... | |
 | Surveying - 1878 - 534 pages
...tivo opposite sides of which are parallel. The content of a Trapezoid equals half the • product of the sum of the parallel sides by the perpendicular distance between them. If the given quantities are the four sides a, b, c, d, of which 5 and d are parallel; then, making... | |
 | Daniel Kinnear Clark - Engineering - 1878 - 1022 pages
...contiguous sides by the natural sine of the included angle. To find the area of a trapczoid. Multiply half the sum of the parallel sides by the perpendicular distance between them. To find the area of a quadrilateral inscribed in a circle. From half the ;um of the four sides subtract... | |
 | Clement Mackrow - 1879 - 552 pages
...length, and & = the perpendicular height, then A = ab. 2. Tofindtlie area of a trapezoid. (Fig. 68.) RULE. — Multiply the sum of the parallel sides \ by the perpendicular distance between them ; half j. the product will be the area. Thus if A = the ; area, J and a = the parallel si des, and... | |
 | Alfred Hiley - 1879 - 228 pages
...parallel sides by the perpendicular distance between them, and divide the product by 2. Or, multiply half the sum of the parallel sides by the perpendicular distance between them. •Note 1. — To find the sum of the parallel sides, when the area and the perpendicular distance... | |
 | William Mitchell Gillespie - Surveying - 1880 - 540 pages
...figm«s, tiro opposite sides of which are parallel. The content of a Trapezoid equals half the product of the sum of the parallel sides by the perpendicular distance between them. If the given quantities are the four sides a, b, c, d, of which 4 and d are parallel ; then, making... | |
 | T W. Stone - 1881 - 134 pages
...side. For the right-angled parallelogram. Multiply one side, the larger, by the less. The trapezoid. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product is the area. The triangle. Multiply the base by the perpendicular, and half the product... | |
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To find the area of a trapezoid. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and then divide the product by two : the quotient will be the area (Bk. 
