 | Arithmetic - 1882 - 526 pages
...perpendicular distance betwcen the sides. V. To find the area of a trapezoid :— Multiply one half the sum of the parallel sides by the perpendicular distance between them.^ PROBLEMS. 1. In a farm 225 rods long and 145 rods wide are how many acres ? #. How many yards of carpeting... | |
 | Clement Mackrow - 1884 - 530 pages
...= the perpendicular height, then A = aJ>. 2. Tu find the area of a trapezoid. (Fig. 68.) KULE. — Multiply the sum of the parallel sides by the perpendicular distance between them ; half the product will be the area. Thus if A = the area, b and a = the parallel sides, and c = the... | |
 | Stephen Roper - Mechanical engineering - 1884 - 740 pages
...the perpendicular height, and take half the product. To find the area of a trapezoid, multiply half the sum of the parallel sides by the perpendicular distance between them ; the product will be the area. To find the area of a quadrilateral inscribed in a circle. — From... | |
 | Joseph Ray - Arithmetic - 1885 - 358 pages
...triangle, the sides 2, 3, and 4 feet respectively. Ans. 2.9047375+sq. ft ART. 314. To FIND THE AREA or A TRAPEZOID. Rule. — Multiply the sum of the parallel sides by the perpendicular breadth ; take half the product. 1. The parallel sides of a trapezoid, FCGD, are 35 and 26 inches;... | |
 | Charles Davies - Geometry - 1886 - 352 pages
...feet from H1e ground : required the breadth of the street. Ans. 77.8875 ft. PROBLEM VI. • To f1nd the area of a trapezoid. RULE. ' Multiply the sum of the parallel sides by the perpend1cular distance between them, and then divide the product hi/ two : the ^uvttent will be the... | |
 | Lumber - 1886 - 170 pages
...of acres in a quadrilateral, having two opposite sides parallel, (such is Fig. 2)— Multiply halt the sum of the parallel sides by the perpendicular distance between them, in rods, and divide the product by 160. EXAMPLE: Given a piece of land ABCE, (Fig. 2) with the side... | |
 | William Mitchell Gillespie - Surveying - 1887 - 722 pages
...figures, two opposite sides of which are parallel. The content of a Trapezoid equals half the product of the sum of the parallel sides by the perpendicular distance between them. If the given quantities are the four sides a, ft, e, d, of which b and d are parallel; then, making... | |
 | Henry Hall - Linotype - 1887 - 520 pages
...multiply the length by the perpon. i H- . 1 1 1 r height. TRA.PEZOID.— To find the area, multiply half the sum of the parallel sides by the perpendicular distance between them. TRIANGLE.— To find tile area, multiply the base by one-halt the perpendicular height. TRAPEZIUM.—... | |
 | Daniel Kinnear Clark - Engineering - 1889 - 1030 pages
...contiguous sides by the natural sine of the included angle. To find the area of a trapezoid. Multiply half the sum of the parallel sides by the perpendicular distance between them. To find the area of a quadrilateral inscribed in a circle. From half the sum of the four sides subtract... | |
 | R. S. Galer - Arithmetic - 1889 - 128 pages
...dimensions of each and solve by rule for triangles. To find the area of a trapezoid: Multiply half the sum of the parallel sides by the perpendicular distance between them. To find the area of a parallelogram: Multiply any side by the perpendicular distance between it and... | |
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To find the area of a trapezoid. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and then divide the product by two : the quotient will be the area (Bk. 
