 AB of the circle into as many equal parts as the polygon is to have sides. With the points A and B as centers and radius AB, describe arcs cutting each other at C.  Observational Geometry - Page 160by William Taylor Campbell - 1899 - 240 pagesFull view - About this book
 | Philip Henry Delamotte - 1874 - 146 pages
...given side. From A with any radius describe a semicircle meeting AB produced. Divide the semicircle into as many equal parts as the polygon is to have sides. From A draw lines through all divisions except the first. From A as centre with AB as radius cut A... | |
 | Robert Griffith Hatfield - Architecture - 1874 - 452 pages
...right angles to as 5 / upon a and b, with ab for radius, describe the arcs, acd and feb ; divide ac into as many equal parts as the polygon is to have sides, and extend those divisions from c towards d ; from the second point of division counting from c towards... | |
 | George E. Webster - 1874 - 136 pages
...one side. Produce line AB from A. With centre A and radius AB, describe semicircle. Divide semicircle into as many equal parts as the polygon is to have sides, say 6. Draw AD from A through the second division, and make it equal to A B. Bisect AB, AD, and produce... | |
 | James Martin (of the Wedgwood inst, Burslem.) - 1876 - 334 pages
...circle A. Problem 134. To construct any regular polygon (say a hexagon) about a given circle A. 1. Divide the circumference into as many equal parts as the polygon is to have sides — six (Pr. 64). 2. Draw radii to these points of division, and produce them beyond the circumference.... | |
 | Daniel Kinnear Clark - Engineering - 1878 - 1022 pages
...EF into four equal parts, and set off three parts equal to those from F to c. Divide the diameter AB into as many equal parts as the polygon is to have sides; and from c draw c D through the second point of division, cutting the circle at D. Then AD is equal... | |
 | Ellis A. Davidson - Geometrical drawing - 1882 - 124 pages
...— From C, with any radius, describe a semicircle cutting the given circle. Divide the semicircle into as many equal parts as the polygon is to have sides. Draw lines from C through each division. The points where these lines cut the circle will be the angular... | |
 | Frederick Edward Hulme - Geometrical drawing - 1882 - 170 pages
...t1-iangle is not found in many text-books we give it here. Divide one side of the triangle, as ED, into as many equal parts as the polygon is to have sides, in this case 5. Produce BE indefinitely beyond E, and through point H, the first of the divisions on... | |
 | Daniel Kinnear Clark - Engineering - 1889 - 1030 pages
...EF into four equal parts, and set off three parts equal to those from F to c. Divide the diameter AB into as many equal parts as the polygon is to have sides; and from c draw c D through the second point of division, cutting the circle at D. Then AD is equal... | |
 | Robert Griffith Hatfield - Architecture - 1895 - 774 pages
...Draw the diameter ac\ upon this erect an equilateral triangle aec, according to Art. 525 ; divide ac into as many equal parts as the polygon is to have sides, as at i, 2, 3, 4, etc.; from e, through each even number, as 2, 4, 6, etc., draw lines 573 cutting... | |
 | Anson Kent Cross - Mechanical drawing - 1898 - 224 pages
...of any number of sides (in this case five) within a -given circle. Draw a diameter AB and divide it into as many equal parts as the polygon is to have sides. With A and B as centres and radius AB, describe arcs intersecting in 5. From 5 draw a straight line through... | |
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