... any two parallelograms are to each other as the products of their bases by their altitudes. PROPOSITION V. THEOREM. 403. The area of a triangle is equal to half the product of its base by its altitude. New Plane and Solid Geometry - Page 138by Webster Wells - 1908 - 298 pagesFull view - About this book
| Walter Nelson Bush, John Bernard Clarke - Geometry - 1905 - 378 pages
...their bases. a. Any two rectangles are to each other as the products of their bases and altitudes. b. **Any two parallelograms are to each other as the products of their bases** and altitudes. SCH. A parallelogram is equal to a rectangle of the same base and altitude. c. Any two... | |
| Edward Rutledge Robbins - Geometry, Plane - 1906 - 268 pages
...Two parallelograms having equal bases are to each other as their altitudes. Proof: CO377. THEOREM. **Any two parallelograms are to each other as the products of their bases by their altitudes.** Proof: (?). 378. THEOREM. The area of a triangle is equal to half the product of its base by its altitude.... | |
| Wisconsin. Department of Public Instruction - Education - 1906 - 124 pages
...102. Two rectangles having equal bases are to each other as their altitudes. 103. Two rectangles are **to each other as the products of their bases by their altitudes.** 104-107. The theorems which give the areas of (1), the rectangle; (2), the parallelogram; (3), the... | |
| Isaac Newton Failor - Geometry - 1906 - 440 pages
...multiplied by their common altitude ; or ABCDE x H. That is, V = B x H. 0, ED 639 COROLLARY. Prisms are **to each other as the products of their bases by their altitudes** ; prisms having equivalent bases are to each other as their altitudes ; prisms having equal altitudes... | |
| International Correspondence Schools - Building - 1906 - 634 pages
...rectangles having equal bases are to each other as their altitudes. 41. The areas of any two rectangles are **to each other as the products of their bases by their altitudes.** Let A and B, Fig. 27, be two rectangles whose altitudes are a and a' and whose bases are b and 6',... | |
| Isaac Newton Failor - Geometry - 1906 - 431 pages
...multiplied by their common altitude ; or ABODE x H. That is, V = B x H. QED 639 COROLLARY. Prisms are **to each other as the products of their bases by their altitudes** ; prisms having equivalent bases are to each other as their altitudes ; prisms having equal altitudes... | |
| Edward Rutledge Robbins - Geometry - 1907 - 428 pages
...Two parallelograms having equal bases are to each other as their altitudes. Proof: (?). 377. THEOREM. **Any two parallelograms are to each other as the products of their bases by their altitudes.** Proof: (?). 378. THEOREM. The area of a triangle is equal to half the product of its base by its altitude.... | |
| Edward Rutledge Robbins - Geometry - 1907 - 428 pages
...prisms having equivalent bases are to each other as their altitudes. ( 607. THEOREM. Any two prisms are **to each other as the products of their bases by their altitudes.** ORIGINAL EXERCISES 1. How many faces has a parallelepiped? Edges? Vertices? How many faces has a hexagonal... | |
| Webster Wells - Geometry - 1908 - 329 pages
...Then, rt. A ABE and DCFare equal. (§§ 61, 104) 3. If from figure ADCE we take A ABE, there remains EH **AC-, if we take A DCF, there remains rect. AF. 283....are necessary for a definite figure ? Why ? Ex. 5.** Emd the ratio of the area of a rhombus to the product of its diagonals. PROP. V. THEOREM 284. The area... | |
| Webster Wells - Geometry, Plane - 1908 - 208 pages
...having equal bases are to each other as their altitudes. PROP. II. THEOREM 277. Any two rectangles are **to each other as the products of their bases by their altitudes.** If a y a R L _j PLANE GEOMETRY — BOOK IV Draw any two rectangles M and N. We then have : Given M... | |
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