 | Claude Irwin Palmer, Daniel Pomeroy Taylor, Eva Crane Farnum - Geometry, Modern - 1924 - 360 pages
...= BF. rt. AA ED = rt. ABFC. ABFD- AAED = nABFE. ABFD- ABFC = UABCD. Why? Why? Why? Why? *324. Cor. The area of a parallelogram is equal to the product of its base and altitude. As a formula, A = bh. Solving the formula for b and h, h and How many parallelograms... | |
 | College Entrance Examination Board - Universities and colleges - 1925 - 198 pages
...a line divides two sides of a triangle proportionally, it is parallel to the third side. 3. Prove: The area of a parallelogram is equal to the product of its base by its altitude. 4.. On the sides BC and AC of any triangle ABC equilateral triangles BCD and CAE are constructed,... | |
 | Julius J. H. Hayn - Geometry, Plane - 1925 - 328 pages
...rectangle both of whose dimensions are incommensurable with unity. R a L RF u Proposition VI. Theorem 252. The area of a parallelogram is equal to the product of its base by its altitude. Hyp.: Given the parallelogram ABCE, with the base AB, and the altitude BF. Det.: To prove... | |
 | Mary Anna Ward - Arithmetic - 1925 - 316 pages
...what must be true of the area of the parallelogram as compared with the area of the rectangle ? m. The area of a parallelogram is equal to the product of its base and altitude. Area of parallelogram = bXa • 32. THE AREA OF A PARALLELOGRAM a. Diagram each... | |
 | Robert Lee Morton - Arithmetic - 1927 - 374 pages
...triangle is equal to one-half of the product of its base by its altitude. 16. How would you show that the area of a parallelogram is equal to the product of its base by its altitude? What is the altitude of an oblique parallelogram? 17. When would you teach the terms, base,... | |
 | Encyclopedias and dictionaries - 1928 - 1958 pages
...whose base la 4 feet 3 Inches and altitude la 2 feet 8 Inches. 4 ft, 3 in. 2 ft, 8 in. = Ï- ft, О The area of a parallelogram is equal to the product of its base arid altitude. A The truth of this statement can be seen by noticing that the triangle at the... | |
 | Raymond Asa Kent, Martha C. Olsen, James R. Skiles - Arithmetic - 1927 - 380 pages
...base times its altitude. 7. A trapezoid is a plane surface two of whose four sides are parallel. 8. The area of a parallelogram is equal to the product of its base multiplied by its altitude. 9. The area of a circle is found by multiplying its radius by 3.1416.... | |
 | College Entrance Examination Board - Mathematics - 1920 - 108 pages
...Prove that two triangles are similar if their homologous sides are in proportion. *11. a) Prove that the area of a parallelogram is equal to the product of its base by its altitude. b) Construct a parallelogram whose area is 12 square inches, and having its base equal to... | |
 | Education - 1905 - 684 pages
...product of the whole secant and its external segment is equal to the square of the tangent. 6. Prove: The area of a parallelogram is equal to the product of its hase and altitude. 6. State and prove the Pythagorean theorem. 7. Inscribe a square in a given circle.... | |
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The area of a parallelogram is equal to the product of its base and its height: A = bx h. 
