| Peter Nicholson - Cabinetwork - 1856 - 518 pages
...rectangle is said to be contained by two of its sides, about any one of its angles. THEOREM 43. 111. The area of a parallelogram is equal to the product of its base and altitude. For the parallelogram ABCD is equal to the rectangle ABEF, which has the same base... | |
| Elias Loomis - Conic sections - 1858 - 256 pages
...the base, and the other the number of linear units contained in the altitude. PROPOSITION V. THEOREM. The area of a parallelogram is equal to the product of its base by its altitude. Let ABCD be a parallelogram, AF its -pn EC altitude, and AB its base ; then is its surface... | |
| Edward Brooks - Geometry - 1868 - 284 pages
...cancelling the equal factor in the second couplet of Cor. 1, we have, ABCD : EFGH:: AB : EF. THEOREM II. The area of a parallelogram is equal to the product of its base and altitude. Let ABCD be a parallelogram, AB its base, and EB its altitude; then will its area... | |
| Elias Loomis - Geometry - 1871 - 302 pages
...base, and the oth«r the number of linear units contained in the altitude. PROPOSITION V. THEOREM. The area of a parallelogram is equal to the product of its base by its altitude. Let ABCD be a parallelogram, AF its altitude, and AB its base ; then is its surface measured... | |
| William Chauvenet - Geometry - 1871 - 380 pages
...is measured by the product of the numerical measures of the lines. PROPOSITION IV.— THEOREM. 10. The area of a parallelogram is equal to the product of its base and altitude. Let ABCD be a parallelogram, k the numerical measure of its base AB, h that of its... | |
| William Chauvenet - Mathematics - 1872 - 382 pages
...lines is measured by the product of the numerical measures of the lines. PROPOSITION IV.—THEOREM. 10. The area of a parallelogram is equal to the product of its base and altitude. Let ABCD be a parallelogram, k the numerical measure of its base AB, h that of its... | |
| Charles Davies - Geometry - 1872 - 464 pages
...product is equal to the area of a rectangle constructed with the lines as sides. PROPOSITION V. THEOREM. The area of a parallelogram is equal to the product of its base and altitude. Let ABCD be a parallelogram, AB its base, and BE its altitude : then will the area... | |
| William Frothingham Bradbury - Geometry - 1872 - 124 pages
...be neglected. 91 Corollary. The area of a square is the square of one of its sides. THEOREM III. 101 The area of a parallelogram is equal to the product of its base and altitude. Let DF be the altitude of the paral- E B_ _ F 0 lelogram ABCD ; then the area of... | |
| William Frothingham Bradbury - Geometry - 1872 - 262 pages
...be neglected. 9. CoroUary. The area of a square is the square of one of its sides. THEOREM III. 10, The area of a parallelogram is equal to the product of its base and altitude. Let DF be the altitude of the paral- E B_ FC lelogram A BCD; then the area of \l... | |
| Henry William Jeans - 1873 - 292 pages
...57°.39577— 57°-29577 — 5729577" whence BAC=53° 38' 30", and a;=100xtan. BAC=407-5. PROB. 63. Since the area of a parallelogram is equal to the product of its base by its altitude,* and the area of triangle =£ area of a parallelogram with same base and altitude, .-. area... | |
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