 | Charles Austin Hobbs - Geometry, Plane - 1899 - 266 pages
...angles are opposite the legs. Consult Prop. 37, Cor. III. and Prop. 8. Proposition 41. Theorem. 52. In an isosceles triangle, the angles opposite the equal sides are equal. HINT. Draw a line bisecting the vertical angle. COB. An equilateral triangle is also equiangular. Proposition... | |
 | George Albert Wentworth - Geometry - 1899 - 496 pages
...always true, just as the converse of a theorem is not always true. PROPOSITION XXII. THEOREM. 145. In an isosceles triangle the angles opposite the equal sides are equal. BDC Let ABC be an isosceles triangle, having AB and AC equal. To prove that ZB = Z C. Proof. Suppose... | |
 | International Correspondence Schools - Civil engineering - 1899 - 722 pages
...the base produced. Thus, in Figs. 32 and33, C BD is the altitude of the triangles AB C. Via. ! 47. In an isosceles triangle, the angles opposite the equal sides are equal. Thus, in Fig. 34, AB — £C; hence, angle C = angle A. Therefore, if two angles of any triangle are... | |
 | 1900 - 728 pages
...the base, or to the base extended. Thus, in Figs. 33 and 34, BD is the altitude of the triangles ABC. In an isosceles triangle, the angles opposite the equal sides are equal. Thus, in Fig. 35, AB = BC; hence, angle C — angle A. In any isosceles triangle, if a perpendicular... | |
 | Adelia Roberts Hornbrook - Arithmetic - 1900 - 428 pages
...isosceles triangle so that the equal sides coincide. Can you see that the following statement is true ? In an isosceles triangle the angles opposite the equal sides are equal. 352. How many degrees are there in each angle of the isosceles triangle ABC? Explain. 353. How many... | |
 | International Correspondence Schools - Coal mines and mining - 1900 - 732 pages
...base, or to the base extended. Thus, in Figs. 33 and altitude in BD is the _ of the triangles ABC. . In an isosceles triangle, the angles opposite the equal sides are equal. Thus, in Fig. 35, AB — BC; hence, angle C = angle A. In any isosceles triangle, if a perpendicular... | |
 | Henry Parker Manning - Geometry, Non-Euclidean - 1901 - 122 pages
...sides and the included angle, of one equal, respectively, to the corresponding parts of the other. 4. Theorem. In an isosceles triangle the angles opposite the equal sides are equal. Bisect the angle at the vertex and use (3). 5. Theorem. The perpendiculars erected at the middle points... | |
 | Henry Parker Manning - Geometry, Non-Euclidean - 1901 - 120 pages
...sides and the included angle, of one Kqual, respectively, to the corresponding parts of the other. 4. Theorem. In an isosceles triangle the angles opposite the equal sides are equal. Bisect the angle at the vertex and use (3). 5. Theorem. The perpendiculars erected at the middle points... | |
 | Alan Sanders - Geometry, Modern - 1901 - 260 pages
...of the other pair of vertical angles. Find the values of the four angles. PROPOSITION X. THEOREM 81. In an isosceles triangle, the angles opposite the equal sides are equal. Let ABC be an isosceles A, having AB = BC. To Prove Z A = Z C. Proof. Draw BD bisecting AC. (§ 55.) B... | |
 | Henry Parker Manning - Geometry, Non-Euclidean - 1901 - 116 pages
...sides and the included anyle, of one equal, respectively, to the corresponding parts of the other. 4. Theorem. In an isosceles triangle the angles opposite the equal sides are equal. Bisect the angle at the vertex and use (3). 5. Theorem. The perpendiculars erected at the middle points... | |
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In an isosceles triangle the angles opposite the equal sides are equal. 
