The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. A D A' Hyp. In triangles ABC and A'B'C', To prove AABC A A'B'C' A'B' x A'C ' Proof. Draw... Elements of Geometry - Page 65by Adrien Marie Legendre - 1841 - 235 pagesFull view - About this book
| Henry Martyn Taylor - Euclid's Elements - 1895 - 657 pages
...ratios AB to DE and BC to EF. Wherefore, if two triangles &c. COROLLARY. If two parallelograms have **an angle of the one equal to an angle of the other,** the ratio of the areas of th« parallelograms is equal to the ratio compounded of the ratios of the... | |
| John Macnie - Geometry - 1895 - 374 pages
...angle B, and angle B to angle C, then the figure is a parallelogram. 73. If two parallelograms have **an angle of the one equal to an angle of the other,** they are mutually equiangular. 74. A parallelogram whose diagonals are equal is a rectangle. 75. A... | |
| Joe Garner Estill - Geometry - 1896 - 144 pages
...increased by twice the square on the median to that side. Amherst College, June, 1896. 1. Two triangles **having an angle of the one equal to an angle of the other, and the** including sides proportional are similar. 2. Inscribe a circle in a given triangle. 3. (1) When are... | |
| Joe Garner Estill - 1896 - 210 pages
...whatever direction the chord is drawn. 6. Prove the ratio between the areas of two triangles which have **an angle of the one equal to an angle of the other.** Define area. 7. Define a regular polygon and prove that two regular polygons of the same number of... | |
| George D. Pettee - Geometry, Plane - 1896 - 253 pages
...respectively ; show that BA is perpendicular to AC. 4. Assuming that the areas of two triangles which have **an angle of the one equal to an angle of the other** are to each other as the products of the sides including the equal angles, prove that the bisector... | |
| George Albert Wentworth - Geometry - 1896 - 50 pages
...trapezoid is equal to the product of the median by the altitude. 374. The areas of two triangles which have **an angle of the one equal to an angle of the other** are to each other as the products of the sides including the equal angles. 375. The areas of two similar... | |
| Joe Garner Estill - 1896 - 186 pages
...respectively ; show that BA is perpendicular to A C. 4. Assuming that the areas of two triangles which have **an angle of the one equal to an angle of the other** are to each other as the products of the sides including the equal angles, prove that the bisector... | |
| Henry W. Keigwin - Geometry - 1897 - 250 pages
...intersection form a parallelogram. (Bryn Mawr, 1894.) 10. Prove that the areas of two triangles which have **an angle of the one equal to an angle of the other** are to each other as the products of the sides including the equal angles. Describe an isosceles triangle... | |
| James Howard Gore - Geometry - 1898 - 232 pages
...SUGGESTION. Compare area of AliE, BEFand. FEC, EDC. PROPOSITION VII. THEOREM. 261. The areas of two triangles **having an angle of the one equal to an angle of the other,** are to each other as the products of the sides including the equal angles. . Let ABC and ADE be two... | |
| Yale University - 1898 - 212 pages
...altitudes, both when the latter are commensurable and incommensurable. 4. The areas of two triangles **having an angle of the one equal to an angle of the other** are to each other as the products of the sides including the equal angles. 5. Given a square the length... | |
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