 | Daniel Leach - Arithmetic - 1851 - 280 pages
...the area of a circle, - — RULE. Multiply half the diameter by half the circumference. Or vmdtiply the square of the diameter by .7854, or the square of the circumference %.0796. 17. What is the area of a cjrcle, whose diameter is 40 rods ? (40X3.1416)^2^62.8320. 62.8320x20=1256.64.... | |
 | Septimus Norris - Locomotives - 1852 - 356 pages
...circumference- As 355 is to 113, so is the circumference to the diameterTo find the Area of a CircleRULE 1- — Multiply the square of the -diameter by -7854; or the square of the circumference by -Jf -07958 ; the product, in either case, will be the areaRULE 2- — Multiply the circumference by... | |
 | Lucius D. Gould - Carpentry - 1853 - 234 pages
...circumference by 3-1416, and the quotient will be the diameter. To find the Area of a Circle. Rule 1. — Multiply the square of the diameter by -7854, or the square of the circumference by -07958; the product, in either case, will be the area. Rule 2. — Multiply the circumference by the diameter,... | |
 | Daniel Leach - Arithmetic - 1853 - 622 pages
...370. To find the area of a circle, — RULE. Multiply half the diameter by half the circumference. Or multiply the square of the diameter by .7854, or the square of the circumference ty.0796. 17. What is the area of a circle, whose diameter is 40 rods ? (40X3.1416)-^2=62.8320. 62.8320x20=1256.64.... | |
 | Septimus Norris - Locomotives - 1854 - 336 pages
...is to 113, so is the cir cumference to the diameter. To find the Area of a Circle. RULE 1.@Multiply the square of the diameter by *7854; or the square of the circumference by MENSURATION OF SURFACES. 109 .07958; the product, in either case, will be the area. RULE 2.@Multiply... | |
 | Daniel Leach - 1857 - 316 pages
...370. To find the area of a circle, — RULE. Multiply half the diameter by half the circumference. Or multiply the square of the diameter by .7854, or the square of the circumference by .0796. 17. What is the area of a circle, whose diameter is 40 rods ? (40X3.1416)-4-2=62.8320. 62.8320x20=1256.64.... | |
 | Thomas William Silloway - Carpentry - 1858 - 236 pages
...circle, multiply half the diameter by half the circumference: or. for a more accurate calculation, multiply the square of the diameter by .7854, or the square of the circumference by .07968. Squaring the circle, as it is termed, is the attempt to ascertain the exact contents of a circle... | |
 | Whitman Peck - Arithmetic - 1868 - 304 pages
...diameter. RULE. — Multiply the circumference by .3183. Art. 212. — To find the area. RULE. — Multiply the square of the diameter by .7854; or the square of the circumference by .07954. Cylinders. — A cylinder is a body whose diameter is uniform, and whose ends are parallel... | |
 | Edward Brooks - Geometry - 1868 - 284 pages
...circumference by one-fourth of the diameter, or the square of the radius by 3.1416. RULE II.—Multiply the square of the diameter by .7854, or the square of the circumference by .07958. 1. What is the area of a circle whose diameter is 50 inches and circumference 157.08 inches? Ans. 19631... | |
 | James Foden - 1869 - 268 pages
...: : 118^ inches. 7_ 22 ) 792 ( 86 in=diameter 66 182 182 To find the area of a circle. RULE 1. — Multiply the square of the diameter by -7854, or the square of the circumference by -07958 ; the product in either case will be the area. RULE 2. — Multiply the circumference by the diameter,... | |
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Multiply the square of the diameter by .7854, or the square of the circumference by .07958. 
