 Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the...  Elementary Algebra - Page 257by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
 | George Albert Wentworth - Arithmetic - 1897 - 440 pages
...This sum will be the complete divisor. POWKRS AND ROOTS. Multiply the complete divisor by the second figure of the root, subtract the product from the dividend, and to the remainder annex the next group for a new dividend. Proceed in this manner until all the groups have been annexed. The result... | |
 | George Albert Wentworth - Arithmetic - 1898 - 424 pages
...root. To this partial divisor add the last figure of the root for a- complete divisor. Multiply this complete divisor by the last figure of the root, subtract...the dividend, and to the remainder annex the next group for a new dividend. Proceed in this manner until all the groups have been thus annexed. The result... | |
 | George Albert Wentworth - 1898 - 424 pages
...root. To this partial divisor add the last figure of the root for a complete divisor. Multiply this complete divisor by the last figure of the root, subtract...the dividend, and to the remainder annex the next group for a new dividend. Proceed in this manner until all the groups have been thus annexed. The result... | |
 | George Albert Wentworth - Arithmetic - 1898 - 424 pages
...root. To this partial divisor add the last figure of the root for a complete divisor. Multiply this complete divisor by the last figure of the root, subtract...the dividend, and to the remainder annex the next group for a new dividend. Proceed in this manner until all the groujjs have been thus annexed. The... | |
 | George Albert Wentworth - Arithmetic - 1898 - 424 pages
...the second figure. This sum will be the complete divisor. Multiply the complete divisor by the second figure of the root, subtract the product from the dividend, and to the remainder annex the next group for a new dividend. Proceed in this manner until all the groups have been annexed. The result... | |
 | George Edward Atwood - Arithmetic - 1899 - 392 pages
...quotient to the root and also to the divisor. Multiply the completed divisor by the last figure in the root, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in the same manner until all the periods have been used. NOTE 1. If the... | |
 | Eugene L. Dubbs - Arithmetic - 1901 - 462 pages
...annex it to the trial divisor for the complete divisor. 4. Multiply the complete divisor by the second figure of the root ; subtract the product from the...dividend, and to the remainder annex the next period for another dividend. 5. Double the part of the root already found for another trial divisor, and proceed... | |
 | William James Milne - Algebra - 1901 - 476 pages
...trial divisor the .figure last found, multiply this complete divisor by the figure of the root found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in this manner until all the periods have been used. The result will be... | |
 | John Appley Ferrell, B. F Sisk - Arithmetic - 1901 - 436 pages
...annexed, and the square of the last figure of the root, 3x3x50 = 450; 3 2 =9. 7500+450+9 = 7959, complete divisor. Multiply the complete divisor by the last figure of the root, subtract the product, and bring down the next period. (4) Proceed as in (3). 1^8489664 =( ) ? Process: Explanation : If after... | |
 | Joseph Benjamin Rider - Engineering - 1901 - 546 pages
...and the other figure or figures of the root, and the square of the last figure to form the complete divisor. Multiply the complete divisor by the last figure of the root, and subtract the product from the dividend. To the remainder annex the next period, and proceed as... | |
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