 | Charles Davies - Algebra - 1851 - 300 pages
...obtain a term of the quotient. 48. Hence, for the division of polynomials we have the following RULE. I. Arrange the dividend and divisor with reference...divisor by this term, and subtract the product from tJte dividend. II. Then divide the first term of the remainder by the first term of the divisor, which... | |
 | Joseph Ray - Algebra - 1848 - 250 pages
...Divide the first term of the remainder by the first term oftlie divisor, the result will be the second term of the quotient. Multiply the divisor by this term, and subtract the product from the last remainder. Proceed in the same manner, and if you obtain 0 for a remainder, the division is said... | |
 | Joseph Ray - Algebra - 1852 - 408 pages
...Divide the first term of the remainder by the first term of the divisor; the result will be the second term of the quotient. Multiply the divisor by this term, and subtract the product from the last remainder. 'Proceed in the same manner, and if you obtain 0 for a remainder, the division is said... | |
 | William Somerville Orr - Science - 1854 - 534 pages
...dividend and divisor, are placed in arithmetic, divide the first term of the dividend by the first term of the divisor ; the result is the first term of the quotient. 3. Then, as in arithmetic, multiply the whole divinar by tho part of the quotient thus found, and subtract... | |
 | Elias Loomis - Algebra - 1855 - 356 pages
...remainder by the first term oj the divisor, the result will be the second term of the quotient. 5. Multiply the divisor by this term, and subtract the product from the last remainder. Continue the same operation till all the terms of the dividend are exhausted. If the... | |
 | Elias Loomis - Algebra - 1856 - 280 pages
...remainder by the first term of the divisor ; the result will be the second term of the quotient. 5. Multiply the divisor by this term, and subtract the product from the last remainder. Continue the same operation till all the terms of the dividend are exhausted. If the... | |
 | Joseph Ray - Algebra - 1857 - 408 pages
...dividend. Divide the first term of the dividend by the first term of the divisor ; the result will be the first term of the quotient. Multiply the divisor...term, and subtract the product from the dividend. Divide the first term of the remainder by the first term of the divisor; the result will be the second... | |
 | Charles Davies - Algebra - 1857 - 408 pages
...divide the first term on the left of the dividend by the first term on the left of the divisor, for the first term of the quotient; multiply the divisor by this term and subtract the product from ike dividend. II. Then divide the fast term of the remainder f>y the first term of the divisor, for... | |
 | Charles Davies - Algebra - 1859 - 324 pages
...dividend: Ш. Divide the first term of the remainder by the first term of the divisor, for the second term of the quotient. Multiply the divisor by this term, and subtract the product from the first remainder, and so on : IV. Continue the operation, until a remainder is found equal to 0, or... | |
 | Charles Davies - Algebra - 1860 - 412 pages
...on the lefi of the dividend by the first term on the left of the divisor, for the first term of th« quotient ; multiply the divisor by this term and subtract...dividend. II. Then divide the first term of the remainder 1'y the first term of the divisor, for the second term of the quotient ; multiply the divisor by this... | |
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... the first term of the quotient ; multiply the divisor by this term, and subtract the product from the dividend. 
