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" If a side of any triangle be produced, the exterior angle is equal to the two interior and opposite angles; and the three interior angles of every triangle are together equal to two right angles. "
The calendar of the University college of Wales - Page lxxiv
by Wales univ, univ. coll. of Wales - 1878
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Moffatt's scholarship answers, by T.J. Livesey (T. Page).

Moffatt and Paige - 1879 - 378 pages
...A is middle point of ED, and— B is middle point of l')F. Exercise to Question 3. . (Sec. III.) " If the square described on one of the sides of a triangle be greater than the squares described on the other two sides of it, the angle contained by those two sides...
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The popular educator, Volumes 5-6

Popular educator - 1880 - 926 pages
...points connected with our prosent subject. Enclid has proved, in the 32nd Proposition of his First Book, that the three interior angles of every triangle are together equal to two right angles, that is, to 180°. Let tho reader bear this fact in mind. Hence it follows that if the measure of any...
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Manual of navigation, Volume 71

Robert Assheton Napier - Navigation - 1880 - 132 pages
...pm .-. elapsed time = 20 minutes = 4 miles = distance from light when right abeam. Proof— Because the three interior angles of every triangle are together equal to two right angles, and the figure formed with the light being a right.angled triangle, and containing one angle of 45°,...
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The Civil Service Manual for 1880-1881: Government Appointments and how to ...

1880 - 186 pages
...any triangle be produced, the exterior angle is eqiul to the two interior and opposite angles ; and the three interior angles of every triangle are together equal to two right angles. Majorca Iceland Teneriffe Madeira Mauritius Java Ceylon Heligoland . . . Spitzbergen ... Fiji I. II....
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The student's guide to the University of Durham, with information respecting ...

1880 - 160 pages
...any triangle be produced, the exterior angle is equal to the two interior and opposite angles ; and the three interior angles of every triangle are together equal to two right angles. (v.) Parallelograms on the same base, and between the same parallels, are equal to one another. (vi.)...
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(Report).

Elizabethan club - 1880 - 156 pages
...side of a triangle be produced the exterior angle is equal to the sum of the two interior angles, and the three interior angles of every triangle are together equal to two right angles. Enunciate the two corollaries to this proposition, and prove one of them. 4. Enunciate and prove the...
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Military examinations. Mathematical examination papers, set for entrance to ...

Woolwich roy. military acad, Walter Ferrier Austin - 1880 - 190 pages
...of a triangle be produced, the exterior angle is equal to the two interior and opposite angles ; and the three interior angles of every triangle are together equal to two right angles. ABC is an isosceles triangle having the sides AB and AC equal. CD is drawn at right angles to AB. Show...
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Euclid for beginners, books i. and ii., with simple exercises by F.B. Harvey

Euclides, Frederick Burn Harvey - Geometry - 1880 - 178 pages
...any triangle be produced, the exterior angle is equal to the two interior and opposite angles ; and the three interior angles of every triangle are together equal to two right angles. Let ABC be a triangle, and let one of its sides, BC, be produced to D. Then it is to be proved that...
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Ten years' Queen's scholarship questions, 1870-9, with answers to arithmetic ...

Education Ministry of - 1880 - 238 pages
...side. Construct the triangle when each side is equal to half the sum of the other two. SECTION III. 1. The three interior angles of every triangle are together equal to two right angles. What ratio does the angle of a regular hexagon bear to a right angle ? 2. Triangles upon the same base...
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Guide to preliminary army examination

John Gibson - 1881 - 302 pages
...any triangle be produced, the exterior angle is equal to the two interior and opposite angles ; and the three interior angles of every triangle are together equal to two right angles. 5. Describe a parallelogram that shall be equal to a given triangle LMN, and have one of its angles...
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