| Edward Brooks - Arithmetic - 1877 - 564 pages
...how far would it fall the last second of a minute ? Ans. 1913f£ feet. CASE II. 844. Given, the last, **term, the common difference, and the number of terms, to find the** first term. 1. Required the first term, the last term being 76, number of terms 25, and common difference... | |
| Edward Brooks - Arithmetic - 1877 - 438 pages
...$105, $110, $115, etc. ; what is the amount for 25 years ? Ans. $225. CASE II. 662. Given, the last **term, the common difference, and the number of terms, to find the** first term. 1. Required the first term, the last term being 41, the number of terms 20, and the common... | |
| Edward Brooks - Arithmetic - 1877 - 232 pages
...$105, $110, $115, etc. ; what is the amount for 25 years ? Ans. $225. CASE II. 662. Given, the last **term, the common difference, and the number of terms, to find the** first term. 1. Required the first term, the last term being 41, the number of terms 20, and the common... | |
| Edward Brooks - Arithmetic - 1877 - 444 pages
...difference. 2. The last term. 4. The number of terms. 5. The sum of all the terms. CASE I. 661. Given, **the first term, the common difference, and the number of terms, to** ftnd the'last term. 1. The first term is 3, the common difference 2, and number of terms 10; required... | |
| Edward Brooks - Arithmetic - 1889 - 482 pages
...difference. 2. The last term. 4. The number of terms. 5. The sum of all the terms. CASE I. 661. Given, **the first term, the common difference, and the number of terms, to find the last term.** 1. The first term is 3, the common difference 2, and nniu^r of terms 10 ; required the last term. SOLUTION.... | |
| Joseph Ray - Arithmetic - 1880 - 420 pages
...operation is, 1 + (20 — 1)X3 = 58, Ans. FORMULA.— I = a + (n — \)d; or I = a — (n — l)d. **Rule. — Multiply the number of terms less one by the common difference,** add the product to the given extreme when the larger is sought, subtract it from the given extreme... | |
| Simon Newcomb - Algebra - 1882 - 302 pages
...Any three of the above five quantities being given, the other two may be found. 279. PROBLEM I. Given **the first term, the common difference and the number of terms, to find the last term.** The first term is here a, second " " " a + d, third " " " a + Ы. The coefficient of d is, in each... | |
| Edward Brooks - Arithmetic - 1895 - 424 pages
...common difference. 2. The last term. 1. The number of terms. 5. The sum of all the terms. 629. Given **the first term, the common difference, and the number of terms, to find the last term.** 1. The first term is 4, the common difference 2, and number of terms 12 ; required the last term. SOLUTION.... | |
| George Washington Hull - Algebra - 1895 - 358 pages
...(2.) The last term, 1. (4.) The common difference, d. (5.) The sum of the terms, s. CASE I. 254. Given **the first term, the common difference, and the number of terms, to find the last term.** 1. Given the first term a, the common difference d, and the number of terms n, to find the last term... | |
| Robert Griffith Hatfield - Architecture - 1895 - 774 pages
...— I - (n — i) d, (120.) we have a rule by which to find the first term, which, in words, is — **Multiply the number of terms less one by the common difference, and** deduct t/ie product from the last term ; the remainder u'ill be the first term. By a transposition... | |
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