 | Edward Brooks - Arithmetic - 1877 - 564 pages
...how far would it fall the last second of a minute ? Ans. 1913f£ feet. CASE II. 844. Given, the last, term, the common difference, and the number of terms, to find the first term. 1. Required the first term, the last term being 76, number of terms 25, and common difference... | |
 | Edward Brooks - Arithmetic - 1877 - 438 pages
...$105, $110, $115, etc. ; what is the amount for 25 years ? Ans. $225. CASE II. 662. Given, the last term, the common difference, and the number of terms, to find the first term. 1. Required the first term, the last term being 41, the number of terms 20, and the common... | |
 | Edward Brooks - Arithmetic - 1877 - 232 pages
...$105, $110, $115, etc. ; what is the amount for 25 years ? Ans. $225. CASE II. 662. Given, the last term, the common difference, and the number of terms, to find the first term. 1. Required the first term, the last term being 41, the number of terms 20, and the common... | |
 | Edward Brooks - Arithmetic - 1877 - 444 pages
...difference. 2. The last term. 4. The number of terms. 5. The sum of all the terms. CASE I. 661. Given, the first term, the common difference, and the number of terms, to ftnd the'last term. 1. The first term is 3, the common difference 2, and number of terms 10; required... | |
 | Edward Brooks - Arithmetic - 1889 - 482 pages
...difference. 2. The last term. 4. The number of terms. 5. The sum of all the terms. CASE I. 661. Given, the first term, the common difference, and the number of terms, to find the last term. 1. The first term is 3, the common difference 2, and nniu^r of terms 10 ; required the last term. SOLUTION.... | |
 | Joseph Ray - Arithmetic - 1880 - 420 pages
...operation is, 1 + (20 — 1)X3 = 58, Ans. FORMULA.— I = a + (n — \)d; or I = a — (n — l)d. Rule. — Multiply the number of terms less one by the common difference, add the product to the given extreme when the larger is sought, subtract it from the given extreme... | |
 | Simon Newcomb - Algebra - 1882 - 302 pages
...Any three of the above five quantities being given, the other two may be found. 279. PROBLEM I. Given the first term, the common difference and the number of terms, to find the last term. The first term is here a, second " " " a + d, third " " " a + Ы. The coefficient of d is, in each... | |
 | Edward Brooks - Arithmetic - 1895 - 424 pages
...common difference. 2. The last term. 1. The number of terms. 5. The sum of all the terms. 629. Given the first term, the common difference, and the number of terms, to find the last term. 1. The first term is 4, the common difference 2, and number of terms 12 ; required the last term. SOLUTION.... | |
 | George Washington Hull - Algebra - 1895 - 358 pages
...(2.) The last term, 1. (4.) The common difference, d. (5.) The sum of the terms, s. CASE I. 254. Given the first term, the common difference, and the number of terms, to find the last term. 1. Given the first term a, the common difference d, and the number of terms n, to find the last term... | |
 | Robert Griffith Hatfield - Architecture - 1895 - 774 pages
...— I - (n — i) d, (120.) we have a rule by which to find the first term, which, in words, is — Multiply the number of terms less one by the common difference, and deduct t/ie product from the last term ; the remainder u'ill be the first term. By a transposition... | |
| |
Having given the first term, the common difference, and the number of terms, to find the last term. 
