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Having given the first term, the common difference, and the number of terms, to find the last term.
Scribner's Engineers' and Mechanics' Companion: Comprising United States ... - Page 11
by J. M. Scribner - 1849 - 264 pages

## The Normal Higher Arithmetic: Designed for Common Schools, High Schools ...

Edward Brooks - Arithmetic - 1877 - 564 pages
...how far would it fall the last second of a minute ? Ans. 1913f£ feet. CASE II. 844. Given, the last, term, the common difference, and the number of terms, to find the first term. 1. Required the first term, the last term being 76, number of terms 25, and common difference...

## The New Normal Written Arithmetic: Designed for Common Schools, Normal ...

Edward Brooks - Arithmetic - 1877 - 438 pages
...\$105, \$110, \$115, etc. ; what is the amount for 25 years ? Ans. \$225. CASE II. 662. Given, the last term, the common difference, and the number of terms, to find the first term. 1. Required the first term, the last term being 41, the number of terms 20, and the common...

## The Normal Union Arithmetic: Graded Course, Part 3

Edward Brooks - Arithmetic - 1877 - 232 pages
...\$105, \$110, \$115, etc. ; what is the amount for 25 years ? Ans. \$225. CASE II. 662. Given, the last term, the common difference, and the number of terms, to find the first term. 1. Required the first term, the last term being 41, the number of terms 20, and the common...

## The New Normal Written Arithmetic: Designed for Common Schools, Normal ...

Edward Brooks - Arithmetic - 1877 - 444 pages
...difference. 2. The last term. 4. The number of terms. 5. The sum of all the terms. CASE I. 661. Given, the first term, the common difference, and the number of terms, to ftnd the'last term. 1. The first term is 3, the common difference 2, and number of terms 10; required...

## The Normal Union Arithmetic: Designed for Common Schools, Normal Schools ...

Edward Brooks - Arithmetic - 1889 - 482 pages
...difference. 2. The last term. 4. The number of terms. 5. The sum of all the terms. CASE I. 661. Given, the first term, the common difference, and the number of terms, to find the last term. 1. The first term is 3, the common difference 2, and nniu^r of terms 10 ; required the last term. SOLUTION....

## Ray's New Higher Arithmetic: A Revised Edition of the Higher Arithmetic

Joseph Ray - Arithmetic - 1880 - 420 pages
...operation is, 1 + (20 — 1)X3 = 58, Ans. FORMULA.— I = a + (n — \)d; or I = a — (n — l)d. Rule. — Multiply the number of terms less one by the common difference, add the product to the given extreme when the larger is sought, subtract it from the given extreme...

## A School Algebra

Simon Newcomb - Algebra - 1882 - 302 pages
...Any three of the above five quantities being given, the other two may be found. 279. PROBLEM I. Given the first term, the common difference and the number of terms, to find the last term. The first term is here a, second " " " a + d, third " " " a + Ы. The coefficient of d is, in each...

## The Normal Standard Arithmetic: By Analysis and Induction, Designed for ...

Edward Brooks - Arithmetic - 1895 - 424 pages
...common difference. 2. The last term. 1. The number of terms. 5. The sum of all the terms. 629. Given the first term, the common difference, and the number of terms, to find the last term. 1. The first term is 4, the common difference 2, and number of terms 12 ; required the last term. SOLUTION....