| George Roberts Perkins - Arithmetic - 1846 - 266 pages
...three times tha common difference ; and so on, for the succeeding terms. Hence, when we have given **the first term, the common difference, and the number of terms, to find the last term,** we have this RULE. To the first term add the product of tlie common difference into the number of terms,... | |
| Charles Davies - Arithmetic - 1846 - 378 pages
...and add the first term to the product. Hence, we have ARITHMETICAL PROGRESSION. CASE I. Having given **the first term, the common difference, and the number of terms, to find the last term.** Multiply the common difference by 1 less than the number of terms, and to the product add the first... | |
| Charles Davies - Arithmetic - 1847 - 368 pages
...than the number of terms, and add the first term to the product. Hence, we have CASE I. Having given **the first term, the common difference, and the number of terms, to find the last term.** Multiply the common difference by 1 less than the number of terms, and to the product add the first... | |
| William Vogdes - Arithmetic - 1847 - 324 pages
...167. CASE 4. The last term, the number of terms, and the common difference given, to find the first **term. RULE. Multiply the number of terms less one, by the common difference,** the product subtracted from the last term, gives the first. EXAMPLES. 1. A person in 13 days travelled... | |
| George Roberts Perkins - Arithmetic - 1849 - 346 pages
...by three times the common difference ; and so on, for the succeeding term. Hence, when we have given **the first term, the common difference, and the number of terms, to find the last term,** we have this RULE. To the first term add the product of the common difference into the number of terms,... | |
| George Roberts Perkins - Arithmetic - 1849 - 356 pages
...terms is 14, and the sum of all the terms is 4970. What is the last term ? Ans. 394. Case XL Given **the first term, the common difference, and the number of terms, to find the** sum of all the terms. RULE. To twice the first term, add the product of the common difference into... | |
| George Roberts Perkins - Arithmetic - 1850 - 364 pages
...by three times the common difference ; and so on, for the succeeding term. Hence, when we have given **the first term, the common difference, and the number of terms, to find the last term,** we have this RULE. To the first term add the product of the common difference it. to the number of... | |
| Charles Davies - Arithmetic - 1850 - 412 pages
...than the number of terms, and add the first term to the product. Hence, we have CASE I. Having given **the first term, the common difference, and the number of terms, to find the last term.** Multiply the common difference by 1 less than the number of terms; and to the product add the first... | |
| George Roberts Perkins - Arithmetic - 1850 - 356 pages
...terms is 14, and the sum of all the terms is 4970. What is the last term ? Ans. 394. Case XI. Given **the first term, the common difference, and the number of terms, to find the** sum of all the terms. RULE. cc/ •£& '> (, •=• S To twice the first term, add the product of... | |
| Charles Guilford Burnham - 1850 - 350 pages
...Therefore, Art. 237. — When the first term, the number of terms, and common difference are given, **to find the last term : RULE. Multiply the number of terms, less** 1, by the common difference, and to the product add the first term, and the sum will be the last term.... | |
| |