 | George Roberts Perkins - Arithmetic - 1846 - 266 pages
...three times tha common difference ; and so on, for the succeeding terms. Hence, when we have given the first term, the common difference, and the number of terms, to find the last term, we have this RULE. To the first term add the product of tlie common difference into the number of terms,... | |
 | Charles Davies - Arithmetic - 1846 - 378 pages
...and add the first term to the product. Hence, we have ARITHMETICAL PROGRESSION. CASE I. Having given the first term, the common difference, and the number of terms, to find the last term. Multiply the common difference by 1 less than the number of terms, and to the product add the first... | |
 | Charles Davies - Arithmetic - 1847 - 368 pages
...than the number of terms, and add the first term to the product. Hence, we have CASE I. Having given the first term, the common difference, and the number of terms, to find the last term. Multiply the common difference by 1 less than the number of terms, and to the product add the first... | |
 | William Vogdes - Arithmetic - 1847 - 324 pages
...167. CASE 4. The last term, the number of terms, and the common difference given, to find the first term. RULE. Multiply the number of terms less one, by the common difference, the product subtracted from the last term, gives the first. EXAMPLES. 1. A person in 13 days travelled... | |
 | George Roberts Perkins - Arithmetic - 1849 - 346 pages
...by three times the common difference ; and so on, for the succeeding term. Hence, when we have given the first term, the common difference, and the number of terms, to find the last term, we have this RULE. To the first term add the product of the common difference into the number of terms,... | |
 | George Roberts Perkins - Arithmetic - 1849 - 356 pages
...terms is 14, and the sum of all the terms is 4970. What is the last term ? Ans. 394. Case XL Given the first term, the common difference, and the number of terms, to find the sum of all the terms. RULE. To twice the first term, add the product of the common difference into... | |
 | George Roberts Perkins - Arithmetic - 1850 - 364 pages
...by three times the common difference ; and so on, for the succeeding term. Hence, when we have given the first term, the common difference, and the number of terms, to find the last term, we have this RULE. To the first term add the product of the common difference it. to the number of... | |
 | Charles Davies - Arithmetic - 1850 - 412 pages
...than the number of terms, and add the first term to the product. Hence, we have CASE I. Having given the first term, the common difference, and the number of terms, to find the last term. Multiply the common difference by 1 less than the number of terms; and to the product add the first... | |
 | George Roberts Perkins - Arithmetic - 1850 - 356 pages
...terms is 14, and the sum of all the terms is 4970. What is the last term ? Ans. 394. Case XI. Given the first term, the common difference, and the number of terms, to find the sum of all the terms. RULE. cc/ •£& '> (, •=• S To twice the first term, add the product of... | |
 | Charles Guilford Burnham - 1850 - 350 pages
...Therefore, Art. 237. — When the first term, the number of terms, and common difference are given, to find the last term : RULE. Multiply the number of terms, less 1, by the common difference, and to the product add the first term, and the sum will be the last term.... | |
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Having given the first term, the common difference, and the number of terms, to find the last term. 
