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" PARALLELOGRAMS upon the same base, and between the same parallels, are equal to one another... "
The First Six and the Eleventh and Twelfth Books of Euclid's Elements: With ... - Page 36
by Euclid, James Thomson - 1837 - 390 pages
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Euclid's Elements of Geometry: Chiefly from the Text of Dr. Simson, with ...

Robert Potts - Geometry - 1876 - 446 pages
...one shall be equal to the angle contained by the two sides, equal to them, of the other. 2. Triangles upon the same base, and between the same parallels, are equal to one another. 3. If the square described upon one of the sides of a triangle be equal to the squares described upon...
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A graduated course of problems in practical plane and solid geometry

James Martin (of the Wedgwood inst, Burslem.) - 1876 - 334 pages
...student enters on the following problems he should thoroughly master the subjoined theorems.) (A.) "Parallelograms upon the same base, and between the same parallels, are equal to each other" (in area). — Euc. I., 35. Ex. ABCD, DBCF— NOTE 1. — " Between the same parallels...
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Edinburgh Medical Journal, Volume 21, Part 1

Medicine - 1876 - 610 pages
...contained angles are equal, and if the third sides are unequal, the contained angles are unequal. 3. Parallelograms upon the same base and between the same parallels are equal. 2. If a straight line falling upon two other straight lines makes the alternate angles equal, those...
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The Madras University Calendar, Volume 1

University of Madras - 1876 - 580 pages
...D. Prove that the exterior angle ACD is greater than the angle ABC. III. Prove that triangles on the same base and between the same parallels are equal to one another. (a) Two equal triangles have two sides of the one equal to two sides of the other. What con elusion...
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Elements of geometry, based on Euclid, book i

Edward Atkins - 1877 - 72 pages
...parallelogram ABCD into two equal parts. Therefore, the opposite sides, &c. QED Proposition 35. — Theorem. Parallelograms upon the same base, and between the...to one another. Let the parallelograms ABCD, EBCF be on the same base BC, and between the same parallels AF, BC ; The parallelogram ABCD shall be equal...
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Solutions to the mathematical examination papers set for admission to the ...

D. Tierney - 1877 - 126 pages
...described would not intersect, and therefore the construction for the triangle required would fail. 2. Parallelograms upon the same base, and between the same parallels, are equal to one another. Shew that if two triangles have two sides of the one equal to two sides of the other, each to each,...
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Inventional Geometry: A Series of Problems : Intended to Familiarize the ...

William George Spencer - Geometry - 1876 - 118 pages
...triangles that shall be equal to each other, and yet not similar ? 137. Can you show that all triangles upon the same base and between the same parallels are equal to one another ? 138. Can you place a circle, whose radius is \\ inch, so that its circumference may touch two points...
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Inventional Geometry: A Series of Problems, Intended to Familiarize the ...

William George Spencer - Geometry - 1877 - 108 pages
...triangles that shall be equal to each other, and yet not similar ? 137. Can you show that all triangles upon the same base and between the same parallels are equal to one another ? 138. Can you place a circle, whose radius is 1J inch, so that its circumference may touch two points...
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John Heywood's complete guide to the standard examinations, consisting of 24 ...

Alfonzo Gardiner - 1878 - 146 pages
...The difference of two numbers is 14, and their sum is 48 : find the numbers. 8. Prove that triangles upon the same base, and between the same parallels, are equal to one another. 9. What do you mean by the " complements of a parallelogram " and by " applying a parallelogram to...
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The elements of plane geometry, from the Sansk. text of Ayra Bhatta, ed. by ...

Āryabhaṭa - 1878 - 100 pages
...same base, and between tht same parallels, are equal to one another. Let the parallelograms AC, BF be upon the same base BC, and between the same parallels AF, BC. The parallelogram AC is equal to the parallelogram BF. First, let the sides AD, DF of the parallelograms...
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