 The equation ad = be gives a — -£, b = — ; so that an d с extreme may be found by dividing the product of the means by the other extreme ; and a mean may be found by dividing the product of the extremes by the other mean.  A School Algebra - Page 295by George Albert Wentworth - 1895 - 362 pagesFull view - About this book
 | Nehemiah Hawkins - Machine-shop practice - 1903 - 362 pages
...PROPORTION. A missing mean may be found by dividing the product of the extremes by the given mean. A missing extreme may be found by dividing the product of the means by the given extreme. SIMPLE PROPORTION is an equality of two simple ratios, as, 9 Ib. : 1 8 Ib. : : 27 cents... | |
 | John Henry Moore - Business mathematics - 1904 - 404 pages
...equal, or that the product of the extremes is equal to the product of the means. 952. Hence, a missing extreme may be found by dividing the product of the means by the given extreme; and a missing mean may be found by dividing the product of the extremes by the given... | |
 | George Albert Wentworth - Algebra - 1906 - 440 pages
...6 d Multiply by bd, ad = bс. The equation ad = be gives be ad a = - » о = — ; d с so that an extreme may be found by dividing the product of the...the product of the extremes by the other mean. If any three terms of a proportion are given, it appears that the fourth terra has one value and but one... | |
 | George Albert Wentworth - 1894 - 218 pages
...product of the means. For, if a : b = c : d, ac then 7 = - • bd Multiplying by bd, ad = be. 207. Hither extreme may be found by dividing the product of the means by the other extreme, and either mean may be found by dividing the product of the extremes by the other mean. If a : b = c :... | |
 | Gustavus Sylvester Kimball - Business mathematics - 1911 - 444 pages
...A missing mean may be found by dividing the product of the extremes by the given mean. 2. A missing extreme may be found by dividing the product of the means by the given extreme. ORAL EXERCISE Find the missing term of the following proportions: 1. 16:4::8:? 4. ?:... | |
 | Joseph Woodwell Ledwidge Hale - Mathematics - 1915 - 230 pages
...will enable us to find any one of the four terms if the other three of them are known, since either mean may be found by dividing the product of the extremes by the other mean. The same will hold true to find either extreme. Proportion gives us a convenient method for finding... | |
 | Thomas J. Foster - Coal mines and mining - 1916 - 1230 pages
...expressed thus, 12 : 6 = 6 : 3. If the two means and one extreme of a proportion are given, the other extreme may be found by dividing the product of the means by the given extreme. Thus, 10 : 5 = 4 : (), then (4X5)-^10 = 2, and the proportion is 10 : 5 = 4 : 2. This... | |
 | Joint Textbook Committee of the Paper Industry - Paper industry - 1921 - 472 pages
...= x = — 0-£- = 14. Here it is seen that if the £o unknown is one of the extremes, its value can be found by dividing the product of the means by the other extreme. Suppose the second term had been* unknown; then the proportion would have been 14 : x = 49 : 28, from... | |
 | Alviso Burdett Stevens - Pharmaceutical arithmetic - 1926 - 184 pages
...It therefore follows that if three terms of a proportion are given the fourth may be found. Either extreme may be found by dividing the product of the means by the other extreme. Either mean may be found by dividing the product of the extremes by the other mean. 373. Example. How... | |
 | Edward Nathan Zern - Coal mines and mining - 1928 - 1298 pages
...thus, 12 : 0 = 6 : 3. If the two means and one extreme of a proportion are given, the other «treme may be found by dividing the product of the means by the given extreme. Thus, 10 : 5 = 4 : (), then (4X5) + 10,- 2, and the proportion U 10 : 5 = 4 : 2. This... | |
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