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" MONEY. 10 mills = 1 cent. 10 cents = 1 dime. 10 dimes = 1 dollar. 10 dollars = 1 eagle. "
The Progressive Higher Arithmetic: For Schools, Academies, and Mercantile ... - Page 125
by Horatio Nelson Robinson - 1875 - 456 pages
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Modern Commercial Arithmetic

Frank Joseph Schneck - Business mathematics - 1902 - 288 pages
...and scale of United States money are shown by the following TABLE 10 mills = 1 cent (0, c., or ct.). 10 cents = 1 dime. 10 dimes = 1 dollar ($). 10 dollars = 1 eagle. United States money is based on the decimal scale. It is expressed as dollars, cents, and mills. The...
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Arithmetic for High Schools, Academies, and Normal Schools

Oscar Lynn Kelso - Arithmetic - 1903 - 302 pages
...dollars, from the eagle on the coin; the quarter-eagle; the half -eagle; the double-eagle. 10 mills = 1 cent 10 cents = 1 dime . 10 dimes = 1 dollar ($) 10 dollars = 1 eagle The scale is uniform and decimal ; the words which express the units, however, do not give this regular...
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Primary Arithmetic

John William Hopkins - Arithmetic - 1903 - 240 pages
...the cost of a 25-lb. sack of flour at $ 3.20 a hundredweight. UNITED STATES MONEY 10 mills (m.) = l cent (^) 10 cents =1 dime 10 dimes =1 dollar ($) 10 dollars =1 eagle Write : Two dollars, fifty cents, and five mills. Six dollars, twenty-eight cents, and four mills....
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Progressive Arithmetic: Third Book, Book 3

William James Milne - Arithmetic - 1906 - 364 pages
...mills 740 cents ; 23,765 cents 4. Write to the nearest cent : $1.667 ; $.264; $4.56; $.812. 10 mills = 1 cent 10 cents = 1 dime 10 dimes = 1 dollar 10 dollars = 1 eagle ROMAN SYSTEM 28. The Roman notation uses seven letters, namely : IVXLCDM 1 5 10 50 100 500 1000 29....
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Progressive Arithmetic, Book 3

William James Milne - Arithmetic - 1906 - 364 pages
...82 cents 88 dollars 37 cents 5 mills 80 cents ; 1 cent 5 mills 740 cents ; 23,765 cents 10 mills = 1 cent 10 cents = 1 dime 10 dimes = 1 dollar 10 dollars = 1 eagle THIRD BOOK ROMAN SYSTEM 28. The Roman notation uses seven letters, namely : IVXL С DM l 5 10 50 100...
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Primary Arithmetic

Bruce Mervellon Watson, Charles Edward White - Arithmetic - 1906 - 232 pages
...(pt.) = 1 quart (qt.) 8 quarts = 1 peck (pk.) 4 pecks = 1 bushel (bu.) UNITED STATES MONEY 10 mills = 1 cent 10 cents = 1 dime 10 dimes == 1 dollar 10 dollars - l eagle AVOIRDUPOIS WEIGHT 16 ounces (oz.) = 1 pound (lb.) 2000 pounds = 1 ton (T.) 100 pounds —...
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Progressive Arithmetic, Complete, Books 2-3

William James Milne - Arithmetic - 1907 - 616 pages
...dollars 82 cents 88 dollars 37 cents 5 mills 80 cents; 1 cent 5 mills 740 cents, 23,765 cents 10 mills = 1 cent 10 cents — 1 dime 10 dimes = 1 dollar 10 dollars = 1 eagle Roman System 22. The Roman notation uses seven letters, namely: IVXLCDM 1 5 10 50 100 500 1000 23....
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School Arithmetic for Grammar Grades

Samuel Hamilton - Arithmetic - 1907 - 422 pages
...$.02025 12 pence = 1 shilling = $.243 20 shillings = 1 pound = $4.8665 United States Money 10 mills = 1 cent 10 cents = 1 dime 10 dimes = 1 dollar 10 dollars = 1 eagle The unit of English money is the pound. The value in United States money of other foreign coins is...
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Hopkins and Underwood's New Arithmetics: First book, Book 1

John William Hopkins - Arithmetic - 1907 - 276 pages
...Find the cost of a 25-lb. sack of flour at $ 3.20 a hundredweight. UNITED STATES MONEY 10 mills (m.)=l cent (¿) 10 cents =1 dime 10 dimes . =1 dollar ($) 10 dollars =1 eagle Write : Two dollars, fifty cents, and five mills. Six dollars, twenty-eight cents, and four mills....
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Hopkins and Underwood's New Arithmetics: 1st- Book, Volume 1

John William Hopkins - Arithmetic - 1907 - 276 pages
...cost of a 25-lb. sack of flour at $ 3.20 a hundredweight. UNITED STATES MONEY 10 mills (m.)=l cent (t) 10 cents =1 dime 10 dimes =1 dollar ($) 10 dollars =1 eagle Write: Two dollars, fifty cents, and five mills. Six dollars, twenty-eight cents, and four mills. Nine...
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