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" The lines joining the middle points of the opposite sides of a quadrilateral bisect each other. "
Elements of Plane and Solid Geometry - Page 72
by Alan Sanders - 1903 - 384 pages
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Plane and Solid Geometry

George Albert Wentworth - Geometry - 1899 - 500 pages
...right angles, the bisectors of the other two angles are parallel. Ex. 533. The two lines that join the middle points of the opposite sides of a quadrilateral bisect each other. Ex. 534. The line that joins the feet of the perpendiculars dropped from the extremities of the base...
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Elements of Plane Geometry

Alan Sanders - Geometry, Modern - 1901 - 260 pages
...angle. 9. Construct an isosceles triangle, having given the base and the vertical angle. 10. ABC is an isosceles triangle, and BE is parallel to AC. Prove...formed by the bisectors of two consecutive angles of a quadrilateral is equal to one half the sum of the other two angles. [§§ 138 and 157.] 14. How...
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Elements of Plane Geometry

Alan Sanders - Geometry, Modern - 1901 - 260 pages
...ABC is an isosceles triangle, and BE is parallel to AC. Prove that BE bisects the exterior angle CUD. 11. The lines joining the middle points of the opposite...formed by the bisectors of two consecutive angles of a quadrilateral is equal to one half the sum of the other two angles. [§§ 138 and 157.] 14. How...
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Plane and Solid Geometry

George Albert Wentworth - Geometry - 1904 - 496 pages
...right angles, the bisectors of the other two angles are parallel. Ex. 533. The two lines that join the middle points of the opposite sides of a quadrilateral bisect each other. Ex. 534. The line that joins the feet of the perpendiculars dropped from the extremities of the base...
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Original Exercises in Plane and Solid Geometry

Levi Leonard Conant - Geometry - 1905 - 154 pages
...opposite leg forms with the base an angle equal to half the vertical angle of the triangle. 65. Each of the lines joining the middle points of the opposite sides of a quadrilateral bisects the line joining the middle points of the diagonals of the quadrilateral. HINT. The line joining...
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Elements of Mechanics Including Kinematics, Kinetics and Statics: With ...

Thomas Wallace Wright - Mechanics - 1906 - 418 pages
...portions of the CG found must coincide.] 40J. The median lines of a triangle pass through one point. 40c. The lines joining the middle points of the opposite sides of a quadrilateral bisect each other. 41. Explain the positions of force, resistance, and fulcrum in the following levers: WheeIbarrow, spade,...
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A Course in Mathematics: Algebraic equations, functions of one variable ...

Frederick Shenstone Woods, Frederick Harold Bailey - Mathematics - 1907 - 412 pages
...middle point of the hypotenuse is equal to one half the hypotenuse. 25. Prove analytically that the line joining the middle points of the opposite sides of a quadrilateral bisect each other. 26. Show that the sum of the squares on the four sides of any quadrilateral is equal to the sum of...
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Exercises in Geometry

Grace Lawrence Edgett - Geometry - 1909 - 104 pages
...are right angles, the bisectors of the other two angles are perpendicular. 2. The two lines that join the middle points of the opposite sides of a quadrilateral bisect each other. 3. The line that joins the feet of the perpendiculars dropped from the extremities of the base of an...
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The Ontario High School Geometry: Theoretical

Alexander H. McDougall - Geometry - 1910 - 316 pages
...sides of a quadrilateral and the middle points of the diagonals are the vertices of a ||gm. 31. The st. lines joining the middle points of the opposite sides of a quadrilateral and the st. line joining the middle points of the diagonals are concurrent. THEORETICAL GEOMETRY THEOREM...
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Plane Geometry

Walter Burton Ford, Earle Raymond Hedrick - Geometry, Modern - 1913 - 272 pages
...areas. Does the area of the parallelogram depend upon the angles included by its sides ? 3. Prove that the lines joining the middle points of the opposite sides of a parallelogram divide it into four parallelograms that are equal in area. 4. Construct a parallelogram...
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