 | George Augustus Walton - Arithmetic - 1864 - 376 pages
...times. Ans. »?¿. Hence the RULE. To find the rate, when the interest, time, and principal are given : Divide the given interest by the interest of the principal for the given time at I per cent. EXAMPLES. At what % will 1. $360 gain $40.80 in 1 y. 5 m. ? Ans. 8%. 2. $100 gain $33J... | |
 | James Stewart Eaton - Arithmetic - 1868 - 356 pages
...put on interest to gain $18 in 2 years? ANALYSIS. $300, at 1 per cent., will gain $6 in 2 years ; A, to gain $18, the rate must be the quotient of $18 -:- $6 = 3. Hence, RULE. Divide the given interest ly the interest of the principal, for the given time, at 1 per cent., and the quotient will be the... | |
 | John Fair Stoddard - Arithmetic - 1868 - 356 pages
...interest on a given principal for a given time is in proportion to the rate per cent. Heuoe the Role. — Divide the given interest by the interest of the principal for the given time, at oxEper cent. Required the rate per cent, if the interest of 1. $325 for 2 months is $3.25. Ans. &%.... | |
 | James Stewart Eaton - Arithmetic - 1866 - 328 pages
...RATE. Ex. 1. At what rate per cent. must $300 be put on interest to gain $18 in 2 years ? ANALYSIS. $300, at 1 per cent., will gain $6 in 2 years ; .•.,...the principal, for the given time, at 1 per cent., and the quotient will be the rate. 2. At what rate per cent. must $142 be put on interest to gain $21.30... | |
 | James Stewart Eaton - Arithmetic - 1867 - 358 pages
...RATE. • Ex. 1. At what rate per cent, must $300 be put on interest to gain $18 in 2 years? ANALYSIS. $300, at 1 per cent., will gain $6 in 2 years ; .•.,...the principal, for the given time, at 1 per cent., and the quotient will be the rate. 2. At what rate per cent, must $142 be put on interest to gain $21.30... | |
 | Whitman Peck - Arithmetic - 1868 - 304 pages
...the time 1^)<tu must be as many years as $12 is contained times hi Ans. 2J years. $30, or 2i years. RULE. — Divide the given interest by the interest of the principal for 1 year. Ex. 4. In what time will $320 yield $72.80, at 7 per cent.? PRINCIPAL. Art. 154. — To find... | |
 | James Stewart Eaton - Arithmetic - 1869 - 336 pages
...RATE. Ex. 1. At what rate per cent, must $300 be put on interest to gain $18 in 2 years? ANALYSIS. $300, at 1 per cent., will gain $6 in 2 years ; /.,...RULE. Divide the given interest by the interest of (he principal, for the given time, at 1 per cent., and the quotient will be the rate. 2. At what rate... | |
 | George Payn Quackenbos - Arithmetic - 1869 - 348 pages
...must $10) $56 be as many times 1 % as $10 is con&f Ans tained times in $55, or 5i. Am. ' '' " " 5J#. RULE. — Divide the given interest by the interest of the principal, for the given time, at 1 $. 348. If, in stead of the interest, the amount is given, subtract the principal from it, to find... | |
 | George Augustus Walton, Electa Nobles Lincoln Walton - Arithmetic - 1869 - 350 pages
...derive the following RULE. — To find the rate, when the interest, principal, and time are given : Divide the given interest by the interest of the principal for the given time at one per cent. ' EXAMPLES. At what rate will 8. $ 1500 gain $ 315 in 8 y7 ? Ans. 7%. 9. $ 3750 gain... | |
 | Henry Bartlett Maglathlin - Arithmetic - 1869 - 332 pages
...as many years to gain $153.68, as 876.84 is contained times in $153.68, which is 2. Therefore, etc. RULE. Divide the given interest by the interest of the principal for 1 year, at the given rate. In what time will the interest of 2. $3000 be $525, at 7 % ? Ans. 2 y. 6... | |
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RULE. Divide the given interest by the interest of the principal, for the given time, at 1 per cent., and the quotient will be the rate. 
