 | Canada - 1893 - 1092 pages
...figure the following Napier's principle for the solution of right-angled spherical triangles : — " The sine of the middle part is equal to the product of the tan" gents of the adjacent parts." 2. In a right-angled spherical triangle given the other two angles,... | |
 | Alfred Hix Welsh - Plane trigonometry - 1894 - 228 pages
...cot J5 s1n A s1n Tí = tan (90° - A) tan (90° - B). THEOREM XIII. In any right spherical triangle, the sine of the middle part is equal to the product of the cosines of the opposite parts. For, cos В + cos С cos A 04 S1n A = ; ; -; . . Til. III. (2). But... | |
 | George Albert Wentworth - Navigation - 1895 - 436 pages
...immediately adjacent are called adjacent parts, and the other two are called opposite parts. Rule I. The, sine of the middle part is equal to the product of the i&ngents of the uaja'-ent parts. Rule II. The sine of the middle part is equal to the product of the... | |
 | George Albert Wentworth - Surveying - 1895 - 422 pages
...immediately adjacent are called adjacent parts, and the other two are called opposite parts. Rule I. The sine of the middle part is equal to the product of the tuX\gents of the tAjacent parts. Rule II. The sine of the middle part is equal to the product of the... | |
 | William Chauvenet - Geometry - 1896 - 274 pages
...: I. The sine of the middle part is equal to the product of the tangents of the adjacent farts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. The correctness of these rules will be shown by taking each of the five... | |
 | Webster Wells - Trigonometry - 1896 - 236 pages
...I. The sine of the middle part is equal to the product of the tangents of the adjacent parís. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. 142. Napier's rules may be proved by taking each circular part in succession... | |
 | George Albert Wentworth - Logarithms - 1897 - 384 pages
...immediately adjacent are called adjacent parts, and the other two are called opposite parts. Rule I. The sine of the middle part is equal to the product of the t&ngents of the Adjacent parts. Rule II. The sine of the middle, part is equal to the product of the... | |
 | English language - 1897 - 726 pages
...a C 1 The sine of the middle part is equal to the product of the tangents of the adjacent parts. 2 The sine of the middle part is equal to the product of the cosines of the opposite parts. Demonstration of the following : An angle and its opposite side are... | |
 | Andrew Wheeler Phillips, Wendell Melville Strong - Trigonometry - 1898 - 362 pages
...C. sin comp R = cos comp 6• cos b. sin comp C=cos compjS cose. Napier's rules may be stated : I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to t he product of the cosines of the opposite... | |
 | Canada - 1899 - 1074 pages
...SPHERICAL TRIGONOMETRY. TIME, 3 HOUR?. 1. Prove with the aid of a figure the following Napier's principle : "The sine of the middle part is equal to the product of the tangents of the adjacent parts. 2. In a right angled spherical triangle is known p a. side adjacent to the right angle... | |
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II. The sine of the middle part is equal to the product of the cosines of the opposite parts. 
