 | William Scott - Algebra - 1844 - 568 pages
...letter. Divide the first term of the dividend by the first terra of the divisor ; the result is the first term of the quotient. Multiply the divisor by this term, and subtract the product from the quotient. . Divide the first term of the remainder by the first term of the divisor; the result is... | |
 | Harvey Goodwin - Mathematics - 1846 - 500 pages
...two; the division of the first term of the dividend by the first term of the divisor gives the first term of the quotient ; multiply the divisor by this term, and subtract the product from the dividend ; bring down as many more of the terms of the dividend as may be required, and repeat the... | |
 | Davis Wasgatt Clark - Algebra - 1846 - 374 pages
...4. Divide the first term of this new dividend by the first term of the divisor ; the result is the second term of the quotient. Multiply the divisor by this term, and subtract as before. 5. Proceed in this manner till the dividend has been exhausted, or till no term of the remainder... | |
 | Elias Loomis - Algebra - 1846 - 376 pages
...the dividend by the first term of the divisor, the result will be thefirst term of the quotient. 3. Multiply the divisor by this term, and subtract the product from the dividend. 4. Divide the first term of the remainder by t he first term of the divisor, the result will... | |
 | Elias Loomis - Algebra - 1846 - 380 pages
...the dividend by the first term of the divisor, the result will be the first term of the quotient. 3. Multiply the divisor by this term, and subtract the product from the dividend. 4. Divide the first term of the remainder by the first term of the divisor, the result will... | |
 | Joseph Ray - Algebra - 1848 - 250 pages
...dividend. Divide the first term of the remainder by the first term of the divisor, the result will be the second term of the quotient. Multiply the divisor...and subtract the product from the last remainder. Proceed in the same manner, and if you obtain 0 for a remainder, the division is said to be exact.... | |
 | Charles Davies - Algebra - 1848 - 300 pages
...term on the left of the dividend by the first term on the left of the divisor, the result is the first term of the quotient ; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives... | |
 | George Roberts Perkins - Algebra - 1848 - 234 pages
...term on the left of the dividend by the first term, on the left of the divisor, the result is the fast term of the quotient; multiply the divisor by this term, and subtract the product from the dividend. \ II. Then divide the fast term of the remainder by the fast term of the divisor, which gives... | |
 | Charles Davies - Algebra - 1851 - 300 pages
...term on the left of the dividend by the first term on the left of the divisor, the result is the first term of the quotient ; multiply the divisor by this term, and subtract the product from tJte dividend. II. Then divide the first term of the remainder by the first term of the divisor, which... | |
 | Joseph Ray - Algebra - 1848 - 250 pages
...dividend Divide the first term of the remainder by the first term oftlie divisor, the result will be the second term of the quotient. Multiply the divisor...and subtract the product from the last remainder. Proceed in the same manner, and if you obtain 0 for a remainder, the division is said to be exact.... | |
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... the first term of the quotient ; multiply the• divisor by this term, and subtract the product from the dividend. 
