 | International Correspondence Schools - Civil engineering - 1899 - 814 pages
...method, however, is the following: In higher works on trigonometry, it has been demonstrated that, in any triangle, the sines of the angles are proportional to the lengths of the sides opposite to them. In other words, sin A : sin B :: BC : AC; or, sin A : sin C::... | |
 | University of Sydney - 1901 - 646 pages
...1. Prove the formula for expanding sinfA+B1) and .simplify Bin(A+90°), cos(— A— 180°), tt 2. In any triangle the sines of the angles are proportional to the opposite sides. 3. If AD be drawn perpendicular to BG in the triangle ABO, prove that BD— CI>—fi... | |
 | International Correspondence Schools - Cartography - 1903 - 846 pages
...method, however, is the following: In higher works on trigonometry, it has been demonstrated that, in any triangle, the sines of the angles are proportional to the lengths of the sides opposite to them. In other words, sin A : sin B : : BC : AC; or, sin A : sin C... | |
 | John G. Anderson - Shop mathematics - 1983 - 554 pages
...lies opposite the smallest angle. In trigonometry, this relationship is developed into the Sine Law: In any triangle, the sines of the angles are proportional to the lengths of the opposite sides. In Fig. 16-12, an acute oblique triangle ABC is shown. An altitude BD... | |
 | Mechanical engineering - 1898 - 498 pages
...by Mr. Darcy E. Lewellen, of Columbus, Ind. Problem 6.— Since angle BDC — 90 degrees, and since in any triangle the sines of the angles are proportional to the sides oppo site, and since sides DA and DB are equal, the opposite angles must be equal. Since the sum of... | |
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In higher works on trigonometry, it has been demonstrated that, in any triangle, the sines of the angles are proportional to the lengths of the sides opposite to them. In other words, sin A : sin B :: BC : AC; or, sin A : sin C:: BC : AB, and sin B :... 
