 The product of two binomials having a common term equals the square of the common term, plus the algebraic sum of the unlike terms multiplied by the common term, plus the algebraic product of the unlike terms.  First Course in Algebra - Page 109by Herbert Edwin Hawkes, William Arthur Luby, Frank Charles Touton - 1917 - 309 pagesFull view - About this book
 | Joseph Victor Collins - Algebra - 1908 - 442 pages
...b) = X* + (a + b)x + ab. »' + (« + b)x + ab Changing this formula into a theorem, we have THEOREM IV. The product of two binomials having a common term equals the square of the commom term, plus the algebraic sum of the other terms times the common term, plus the algebraic product... | |
 | Joseph Victor Collins - Algebra - 1910 - 332 pages
...a)(x + b) = a?+(a + b)x + ab. tf + (a + fyx + ab Changing this formula into a theorem, we have THEOREM IV. The product of two binomials having a common term equals the square of the common term, and the algebraic sum of the other terms times the common term, and the algebraic product of the other... | |
 | John Charles Stone, James Franklin Millis - Algebra - 1911 - 698 pages
...product of two binomials having a common term, take the square of tlie common term, plus the alyebntic sum of the unlike terms multiplied by the common term, plus the algebraic product of the unlike terms. (a + by- = a- + 2ab + ba-and (a - 6)2 = a2 - 2 ab + 62. Hence, to square a binomial, take the square... | |
 | Joseph Victor Collins - Algebra - 1911 - 330 pages
...-160-'. 13. 25^-36. 14. 4me-l. 15. 49 a4 -|62. 16. a2m-b2". 17. ¡- ж-yz2 — 25 n2. 66. THEOIÍEM IV. The product of two binomials having a common term equals the square of the common term, and the algebraic sum of the other two terms times the common term, and the algebraic product of the... | |
 | John Charles Stone, James Franklin Millis - Algebra - 1913 - 330 pages
...+ 6) = z2 + (а + 6) x + ab. Hence, to find the product of two binomials having a common term, take the square of the common term, plus the algebraic...term, plus the algebraic product of the unlike terms. (a + by- = a2 + 2 ab + 62 and (a - 6)2 = a2 — 2 ab + *'. ELEMENTARY ALGEBRA Hence, the square of... | |
 | John William Hopkins, Patrick Healy Underwood - Algebra - 1912 - 362 pages
...а; +8 х - 8 а; -3 а; +3 а^ + 8 a/ a? — 8a; -За;- 24 + 3 z - 24 a? + 5a;-24 a?-5a;-24 Hence, the product of two binomials having a common term equals the square of the common term, the algebraic sum of the other two terms multiplied by the common term, and the product of the other... | |
 | George Wentworth, David Eugene Smith - Algebra - 1913 - 478 pages
...7 x + a x +5 x +b 3?+ 7 ж б ж + 35 я? + ase, Ъх + ab аг" + 12ж + 35 ж2+(а + г>)ж + а6 The product of two binomials having a common term equals the square of the common term, plus the product of the common term by the sum of the other terms, plus the product of the other terms. That... | |
 | Frederick Charles Kent - Algebra - 1913 - 292 pages
...product of x and the sum of 3 and 5. In general, IX (x + a)(x + b) = x" + (a + b)x + ab. This means that the product of two binomials having a common term equals the square of the common term plus the product of the common term and the algebraic sum of the other two terms, plus also the product of the... | |
 | George Albert Wentworth - 1913 - 296 pages
...of their squares. That is, (a + ft) (a - ft) = a2 - ft2. Therefore (3m + 4) (3m- 4) = 9m2 - 1в. 4. The product of two binomials having a common term equals the square of the common term, plus the product of the common term by the sum of the other terms, plus the product of the other terms. That... | |
 | Joseph Victor Collins - Algebra - 1913 - 362 pages
...Ans. (5 x3 + 1) (5 z 1 - 1) = ? (3 z" - 2 yp) (3 z" + 2 yp) = ? IV. O + a(jr + 6=jr 2 + ( THEOREM. The product of two binomials having a common term equals the square of the common term, and the algebraic sum of the other terms times the common term, and the algebraic product of the other... | |
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