 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1913 - 484 pages
...and 5 in. and the angle included by them equal 45°. Find the area. PROPOSITION V. THEOREM 355. The area of a triangle is equal to one half the product of its base and altitude. B Proof. Construct O ABDC. The diagonal of a parallelogram divides it into two equal triangles. .'.... | |
 | James Robert Overman - Arithmetic - 1923 - 396 pages
...triangle is ^xABxDC. But AB is the base of the triangle and DC is the altitude (Figure 30). Therefore: The area of a triangle is equal to one half the product of the base by the altitude, or 4 Figure 30. 191 lelogram, or the triangle. Probably the easiest method... | |
 | 1924 - 368 pages
...parallelogram. The area of the parallelogram is b X h. Therefore the area of the triangle is equal to The area of a triangle is equal to one half the product of the base by the altitude. To find the area of a triangle it is necessary to have the base and the altitude... | |
 | Thomas Alexander, Charles Madison Sarratt - Arithmetic - 1924 - 462 pages
...is the altitude of the parallelogram? Of the triangle? Compare the bases, altitudes, and areas. The area of a triangle is equal to one half the product of the base by the altitude. A=b-^. A=\xa. A=bxa6. mm *338 7. Find the missing element (A, a, b) for each... | |
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1925 - 504 pages
...the base and a side changes but the base and side remain constant? PROPOSITION V. THEOREM 368. The area of a triangle is equal to one half the product of its base and altitude. AB Given AABC, having base b and altitude h. To prove AABC = % b X h. Proof STATEMENTS 1. Draw BD ||... | |
 | Encyclopedias and dictionaries - 1928 - 1958 pages
...altitude. Reducing to units of the same denomination. 1 Acre = 43.5IÎO sq. ft. 21780 h = 66 ft. 330 The area of a triangle is equal to one half the product of its base and altitude. In the figure, the triangle, ABC, is obviously the same size as the triangle BDC. The two triangles... | |
 | Military Academy, West Point - 1934 - 964 pages
...to each other and intersecting at O. Then U3'+<JBH5c7-'+073' = (the diameter)'. 10 (a) Theorem: The area of a triangle is equal to one half the product of its perimeter by toe radius of the inscribed circle. (6) If an arc of 45° on one circumference is equal... | |
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The area of a triangle is equal to one half 'the product of its base and altitude. 
