 | Benjamin Greenleaf - Arithmetic - 1857 - 336 pages
...figure last annexed by the figure annexed to the root, and subtract the product from the dividend. To the remainder bring down the next period for a new dividend. Double the root already found for a new divisor, and continue the operation as before, till all the... | |
 | Daniel Adams - 1858 - 354 pages
...obtained, together with the cube of the last quotient, to the former product for a subtrahend. VII. Subtract the subtrahend from the dividend, and to...remainder bring down the next period for a new dividend, vith which proceed as before, till the work is finished. NOTE 1 . — If it happens that the divisor... | |
 | Benjamin Greenleaf - Arithmetic - 1858 - 472 pages
...for a true divisor. Multiply the true divisor by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Multiply the square of (lie root figures already found by 3, and to the product annex two ciphers for... | |
 | Elias Loomis - Algebra - 1858 - 394 pages
...figure. 5. Multiply the divisor thus increased by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 6. Take three hundred times the square of the whole root now found for a new trial divisor, and continue... | |
 | Thomas William Silloway - Carpentry - 1858 - 236 pages
...the right hand of the divisor. Multiply the divisor by the last quotient-figure, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, 4th, Double the quotient already found for a partial divisor, and from these find the next figure in... | |
 | Charles Haynes Haswell - Measurement - 1858 - 350 pages
...period, and place its root in the quotient ; subtract the square number from the left-hand period, and to the remainder bring down the 'next period for a new dividend. Double the root already found for a divisor ; find how many times this incomplete divisor is contained... | |
 | Benjamin Greenleaf - Arithmetic - 1858 - 332 pages
...represent? What is the rule for extracting the cube root ? Subtract the subtrahend from the dicidend, and to the remainder bring down the next period for a new dicidend, with which proceed at before; and so on, till the whole is completed. NOTE 1. — In separating... | |
 | Benjamin Greenleaf - Arithmetic - 1858 - 458 pages
...for a true divisor. Multiply the true divisor by the last figure of the root : subtract the product from the dividend, and to the remainder bring down the next period far a new dividend. To the last true divisor and the number immediately over it, add the square of... | |
 | Benjamin Greenleaf - Arithmetic - 1859 - 334 pages
...its contents ? What part of Fig. 4 does it represent ? What is the rule for extracting the cube root? Subtract the subtrahend from the dividend, and to...next period for a new dividend, with which proceed ai before ; and so on, till the whole is completed. NOTE 1. — In separating the given number into... | |
 | Charles Guilford Burnham - 1859 - 338 pages
...the last ; under these write the cube of the last quotient figure, and call their sum the subtrahend. Subtract the subtrahend from the dividend, and to...remainder bring down the next period, for a new dividend, and proceed as before, till the work is finished. EXAMPLES. 2. What is the cube root of 1906624 ? ,... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
