 | Edward Albert Bowser - Trigonometry - 1892 - 392 pages
...and со. B are the opposite parts. Then Napier's Rules are : (1) The sine of the middle part equals the product of the tangents of the adjacent parts. (2) The sine of the middle part equals the product of the cosines of the opposite parts. NOTE 1. — It will assist... | |
 | Edward Albert Bowser - Trigonometry - 1894 - 206 pages
...and co. B are the opposite parts. Then Napier's Rules are . (1) The sine of the middle part equals the product of the tangents of the adjacent parts. (2) The sine of the middle pan equals the product of the cosines of the opposite parts. NOTE 1. — It will assist... | |
 | Ephraim Miller - Plane trigonometry - 1894 - 222 pages
...that Ntger's Rules apply in either case. 92. Napier's Rules. 1. The sine of the middle part equals the product of the tangents of the adjacent parts. 2. The sine of the middle part equals the product of the cosines of the opposite parts. 93. That Napier's Rules, the... | |
 | Alfred Hix Welsh - Plane trigonometry - 1894 - 228 pages
...are known as Napier1s Analogies. THEOREM XII. In any right spherical triangle, the sine of the middle part is equal to the product of the tangents of the adjacent parts. For, sin b cot с — sin A cot С „7 „ ._ .,.,. cos A = ; . . . Th. II, Cor. III. cos b But С... | |
 | Webster Wells - Trigonometry - 1896 - 236 pages
...parts, and the remaining two the opposite parts. Then Napier's rules are : I. The sine of the middle part is equal to the product of the tangents of the adjacent parís. II. The sine of the middle part is equal to the product of the cosines of the opposite parts.... | |
 | William Chauvenet - Geometry - 1896 - 274 pages
...the two sides including it are regarded as adjacent parts. The rules are : I. The sine of the middle part is equal to the product of the tangents of the adjacent farts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts.... | |
 | English language - 1897 - 726 pages
...rules : « a = b b sin A = tan A. tan B cos A = C sin B = c a cos B = a C 1 The sine of the middle part is equal to the product of the tangents of the adjacent parts. 2 The sine of the middle part is equal to the product of the cosines of the opposite parts. Demonstration of the... | |
 | James William Nicholson - Trigonometry - 1898 - 204 pages
...90°— c, 90°— A and 90°— Б are adjacent parts, and a and b opposite parts. 129. Rules. l. The sine of any part is equal to the product of the tangents of the adjacent parts. ll. The sine of any part is equal to the product of the cosines of the opposite parts. NOTE. — These... | |
 | Andrew Wheeler Phillips, Wendell Melville Strong - Trigonometry - 1898 - 362 pages
...comp 6• cos b. sin comp C=cos compjS cose. Napier's rules may be stated : I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to t he product of the cosines of the opposite parts. 84:.... | |
 | Canada - 1899 - 1074 pages
...HOUR?. 1. Prove with the aid of a figure the following Napier's principle : "The sine of the middle part is equal to the product of the tangents of the adjacent parts. 2. In a right angled spherical triangle is known p a. side adjacent to the right angle and P the angle... | |
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I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. 
