 | Education - 1878 - 446 pages
...last figure of the root, and then add this last sum to the trial divisor for the complete divisor. 7. Multiply the complete divisor by the last figure of...root, and subtract the product from the dividend. 8. Find a new trial divisor as before and continue the operation in the same manner until all the periods... | |
 | Milton Browning Goff - Arithmetic - 1876 - 462 pages
...result we annex to both divisor and root already found, and then multiply the divisor thus increased by the last figure of the root, and subtract the product from the dividend. Result, 895. EXAMPLE 3. — Find the square root of 5852.25. SOLUTION. EXPLANATION — Since loths... | |
 | Popular educator - 1876 - 854 pages
...part of the root already obtained, and also to the partial divisor. Multiply the divisor thus formed by the last figure of the root, and subtract the product from the dividend, bringing down the next period to the right of the remainder for a dividend. Continue the operation... | |
 | Frank Eugene Kidder - Architecture - 1886 - 640 pages
...square of the second figure in the root; multiply toe stun l>> thela-t figure in the root, and subtract from the dividend; to the remainder annex the next period, and proceed as before. \Vheii the trial divisor is greater than the dividend, write a cipher in the root, annex the next period... | |
 | Christian Brothers - Arithmetic - 1888 - 484 pages
...annex the quotient to the root and also to the divisor. IV. Multiply the divisor as it now stands, by the last figure of the root, and subtract the product from the dividend. V. Proceed in the same manner with the other periods, until all have been used. NOTES. — 1. If on... | |
 | Frank Eugene Kidder - Architecture - 1892 - 1058 pages
...square of the second figure, in the root; multiply the sum by the last figure in the root, and subtract from the dividend; to the remainder annex the next period, and proceed as before. When the trial divisor is greater than the dividend, write a cipher in the root, annex the next period to the... | |
 | Wm. M. Peck - 1894 - 310 pages
...and use the quotient as the next order of the root. (Note I.) 5. Multiply the divisor by this order of the root and subtract the product from the dividend. To the remainder found annex the next order of the power. (Note 2.) 6. From this number subtract three times the product... | |
 | John Marvin Colaw, John Kelley Elkwood - Arithmetic - 1900 - 450 pages
...last found for a complete divisor. Multiply this complete divisor by the part of the root last found, subtract the product from the dividend, to the remainder annex the next group for a new dividend, and proceed as before until all of the groups have been thus annexed. 1.... | |
 | Joseph Benjamin Rider - Engineering - 1901 - 546 pages
...the quotient as the next figure of the root. Annex this quotient to the right of the trial divisior to form the complete divisor. Multiply the complete...remainder annex the next period, and proceed as before. NOTE. — When the given number contains a decimal, separate the number into periods of two figures... | |
 | Robert Wahl, Max Henius - Brewing - 1902 - 1288 pages
...I i 2|52 Write the second figure of the root (2) after the new divisor •\»), then multiply this divisor by the last figure of the root, and subtract the product from the dividend (52). Thus: IV 1.52.27.56 (12 ii 22 52 44 Then bring down the next period and continue as before. Thus... | |
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... by the last figure of the root, and subtract the product from the dividend ; to the remainder bring down the next period for a new dividend. 
