 | John Gale HUN (and MAC INNES (Charles Ranald)), Charles Ranald MacInnes - Trigonometry - 1911 - 234 pages
...classed as either a middle and two adjacent parts, or a middle and two opposite parts. 82. Napier's Rule. The sine of the middle part is equal to the product of the tangents of the adjacent parts, and to the product of the cosines of the opposite parts. Since there are ten combinations of five things... | |
 | Alfred Monroe Kenyon, Louis Ingold - Trigonometry - 1913 - 184 pages
...1. The sine of the middle part is equal to the product of the cosines of the opposite parts. BULE 2. The sine of the middle part is equal to the product of the tangents of the adjacent parts. These rules may be remembered by the alliteration of the first vowel in the words cosine and opposite,... | |
 | Alfred Monroe Kenyon, Louis Ingold - Trigonometry - 1913 - 300 pages
...both adjacent or both opposite. Napier's rules refer to these circular parts and are as follows : EULE 1. The sine of the middle part is equal to the product of the cosines of the opposite parts. RULE 2. The sine of the middle part is equal to the product of the tangents... | |
 | Robert Édouard Moritz - Trigonometry - 1913 - 562 pages
...the product of the tangents of the adjacent parts, and the five on the left are contained in Rule 2. The sine of the middle part is equal to the product of the cosines of the opposite parts. These two rules are known as Napier,s Rules of the Circular Parts. 17.... | |
 | George Wentworth, David Eugene Smith - Trigonometry - 1915 - 388 pages
...tan2 (45° - £ В) = tan £ (Л - «) tan i (Л + «). NAPIER'8 RULE8 (§ 176) 1. T/¿e Ätwe of any middle part is equal to the product of the tangents of the adjacent parts. 2. The sine of any middle part is equal to the product of .the cosines of the opposite parts. PRINCIPAL FORMULA8 OF... | |
 | Claude Irwin Palmer, Charles Wilbur Leigh - Logarithms - 1916 - 348 pages
...the opposite parts. Napier's rules are then stated as follows: (1) The sine of a middle part equals the product of the tangents of the adjacent parts. (2) The sine of a middle part equals the product of the cosines of the opposite parts. It may assist in remembering... | |
 | George Neander Bauer, William Ellsworth Brooke - Trigonometry - 1917 - 196 pages
...follows : The sine of the middle part is equal to the product of the cosines of the opposite parts. The sine of the middle part is equal to the product of the tangents of the adjacent parts.* * To associate cosine with opposite and tangent with adjacent, it may be noticed that the words cosine... | |
 | George Neander Bauer, William Ellsworth Brooke - Trigonometry - 1917 - 344 pages
...middle part and со с and со ß are opposite parts. Napier's rules may now be stated as follows : The sine of the middle part is equal to the product of the cosines of the opposite parts. Tlie sine of the middle part is equal to the product of the tangents... | |
 | James Atkins Bullard, Arthur Kiernan - Trigonometry - 1922 - 252 pages
...sine of a middle part is equal to the product of the cosines of the opposite parts. 2. The sine of a middle part is equal to the product of the tangents of the adjacent parts. (61) The parts mentioned in the rules are the five so-called circular parts of the right triangle;... | |
 | Smithsonian Institution - Elliptic functions - 1922 - 410 pages
...omitted. The sine of the middle part is equal to the product of the tangents of the adjacent parts. The sine of the middle part is equal to the product of the cosines of opposite parts. From these rules the following equations follow: sin a = sin с sin a, tan... | |
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I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. 
