 | Francis Walkingame - 1833 - 204 pages
...the whole distance 366 miles. Case 3. The ttvo extremes and the common difference being given, lojind the number of terms. RULE. Divide the difference of...the common difference, and the quotient increased by unity is the number sought. (6) A person travelling into the country, went 3 miles the first day, and... | |
 | John Rose - Arithmetic - 1835 - 192 pages
...Given the extremes (the first and last terms,) and the common difference, to find the number of terms. Divide the difference of the extremes, by the common difference, and the quotient increased by 1 will be the number of terms required. 1. The extremes are 2 and 53, and the common difference 3; what... | |
 | George Willson - Arithmetic - 1836 - 202 pages
...difference, to find the number of terms. RULE. — Divide the difference of the extremes by the cormr-on difference, and the quotient increased by 1 is the number of terms. 7. A man travelling a journey, went 18 miles the first day, and increased his distance each day by... | |
 | Nathan Daboll - Arithmetic - 1837 - 262 pages
...8c2. common difference, and 121. the V>hole debt. PROBLEM III. Given the first term, last term, and common difference, to find the number of terms. RULE....difference, and the quotient increased by 1 is the num ber of terms. EXAMPLES. If the extremes be 2 and 45, and 45, and the com mon difference^; what... | |
 | Charles Guilford Burnham - Arithmetic - 1837 - 266 pages
...books purchased. Therefore — When the first and last terms, and the common difference are given, to find the number of terms : RULE. Divide the difference...extremes by the common difference, and the quotient will be 1 less than the number of terms. 10. If the first term of a series be 2, and the last term... | |
 | George Willson - Arithmetic - 1838 - 194 pages
...common difference of their ages ? Ans. 2 years. PROBLEM IV. — Given the first term, last term, and common difference, to find the number of terms. RULE....the quotient increased by 1 is the number of terms. 7. A man travelling a journey, went 18 miles the first day, and increased his distance each' day by... | |
 | George Willson - Arithmetic - 1838 - 194 pages
...common difference of their ages ? Ans. 2 years. PROBLEM IV. — Given the first term, last term, and common difference, to find the number of terms. RULE....the quotient increased by 1 is the number of terms. 7. A man travelling a journey, went 18 miles the first day, and increased his distance each day by... | |
 | Zadock Thompson - Arithmetic - 1838 - 174 pages
...first term, the last term, and the common differenet given to find the number of terms. . . ROLE. — Divide the difference of the extremes by the common difference, and the quotient, increased by 1, will be the answer. 2. If the first term of a series be 8. the last 108, and the common difference... | |
 | Benjamin Greenleaf - Arithmetic - 1839 - 356 pages
...returning with them one by one to the basket ? Ans. 288090 miles, 2 rods. PROBLEM HI. Given the extremes and the common difference, to find the number of terms....the common difference, and the quotient increased by one, will be the number of terms required. 9. If the extremes are 3 and 45, and the common difference... | |
 | Nathan Daboll - 1839 - 220 pages
...Ans. 22 miles 3 furlongs 100 yards. CASE IV. TAe first term, last term and common difference given, to find the number of terms. RULE. Divide the difference...common difference, and the quotient increased by 1, will be the number of terms. EXAMPLES. 1 . A man bought cloth in arithmetical progression, giving 5... | |
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Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terns. EXAMPLES. 1. If the extremes be 3 and... 
