A Practical System of Mensuration of Superficies and Solids ... |
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Page 21
... whole figure , so many square inches it is said to contain , which , in the present case , A we find to be 16. Again : supposing the 8 C 回 E square figure to contain 4 square miles of land , then 4 miles of land would be 4 times 4 , or ...
... whole figure , so many square inches it is said to contain , which , in the present case , A we find to be 16. Again : supposing the 8 C 回 E square figure to contain 4 square miles of land , then 4 miles of land would be 4 times 4 , or ...
Page 23
... whole figure . Now , the number of square inches in one of the small parallelo- grams is 9 , and the number of linear inches in the breadth BC is 7. Therefore the product of the length into the breadth is 63 square inches . It is ...
... whole figure . Now , the number of square inches in one of the small parallelo- grams is 9 , and the number of linear inches in the breadth BC is 7. Therefore the product of the length into the breadth is 63 square inches . It is ...
Page 26
... whole contents of the room as if there were no windows and doors ; theu find the contents of the windows and doors , and deduct the amount from the whole : the remainder will be the true answer in square feet . Next , divide the number ...
... whole contents of the room as if there were no windows and doors ; theu find the contents of the windows and doors , and deduct the amount from the whole : the remainder will be the true answer in square feet . Next , divide the number ...
Page 34
... whole , therefore , is equal to this product multiplied into the number of sides . Ex . 1. Required the area of a regular hexagon , each of whose sides , AB , & c . , is 45 feet , and the perpendicular , CD , 24 feet . We first multiply ...
... whole , therefore , is equal to this product multiplied into the number of sides . Ex . 1. Required the area of a regular hexagon , each of whose sides , AB , & c . , is 45 feet , and the perpendicular , CD , 24 feet . We first multiply ...
Page 36
... of an irregular figure , at five equi- distant places , being 8.2 , 7.4 , 9.2 , 10.2 , 8.6 , and the whole length 39 , required the area . OPERATION . 8.2 35.2 = sum . 8.6 39 2 36 MENSURATION . Area of Irregular Figures, 36-38.
... of an irregular figure , at five equi- distant places , being 8.2 , 7.4 , 9.2 , 10.2 , 8.6 , and the whole length 39 , required the area . OPERATION . 8.2 35.2 = sum . 8.6 39 2 36 MENSURATION . Area of Irregular Figures, 36-38.
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A Practical System of Mensuration of Superficies and Solids: Designed ... J. M. Scribner No preview available - 2017 |
A Practical System of Mensuration of Superficies and Solids J. M. Scribner No preview available - 2022 |
A Practical System of Mensuration of Superficies and Solids: Designed ... J. M. Scribner No preview available - 2017 |
Common terms and phrases
12 feet 18 inches 20 feet 9 feet ABCD ABFD assumed cube avoirdupois axis base 26 breadth centre chord circle whose diameter Circular Sector circular segment circumfer circumference circumscribed contained convex surface Cube Root cubic feet cubic ft cubic inches cylinder cylindrical ring decimal diff divide the product ellipse ends entire surface equal extract the square feet 6 inches feet long find the area find the Solidity frustrum gallon half hypotenuse inner diameter inscribed square lateral surface length miles multiply the sum Nonagon number of degrees number of sides number of square OPERATION parabola parallel sides parallelogram pentagonal pyramid perpendicular distance perpendicular height plane prism PROBLEM radius regular pentagonal regular Polygon Required the area Required the solidity rhombus right angled triangle Rule Rule.-I slant height solid contents sphere spherical segment spheroid square feet square rods square root square yards thickness trapezium zoid zone
Popular passages
Page 53 - RULE. Find the area of the sector which has the same arc, and also the area of the triangle formed by the chord of the segment and the radii of the sector. Then...
Page 35 - Now, since the areas of similar polygons are to each other as the squares of their homologous sides...
Page 79 - A sphere is a solid terminated by a curved surface, all the points of which are equally distant from a point within called the centre.
Page 80 - A zone is a portion of the surface of a sphere included between two parallel planes.
Page 90 - ... to three times the square of the radius of the segment's base, add the square of its height ; then multiply the sum by the height, and the product by .5236 for the contents.
Page 49 - From 8 times the chord of half the arc subtract the chord of the whole arc, and ' of the remainder will be the length of the arc nearly.
Page 72 - RULE.* To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends, and this last sum multiplied by £ of the height will give the solidity.
Page 51 - As 360 degrees is to the number of degrees in the arc of the sector, so is the area of the circle to the area of the sector.
Page 91 - From three times the diameter of the sphere subtract twice the height of the segment; multiply this remainder by the square of the height and the product by 0.5236.
Page 39 - A Circle is a plane figure bounded by a curve line, called the Circumference, which is everywhere equidistant from a certain point within, called its Centre.