First Part of an Elementary Treatise on Spherical Trigonometry |
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... spherical triangles which contain two or more right angles ( 522 ) , ( 534 ) , ( 535 ) , ( 539 ) , 18 10 10 13 The sum of the angles of a spherical right triangle ( 540 ) , 14 SECTION II . Solution of Spherical Right Triangles , 16 when ...
... spherical triangles which contain two or more right angles ( 522 ) , ( 534 ) , ( 535 ) , ( 539 ) , 18 10 10 13 The sum of the angles of a spherical right triangle ( 540 ) , 14 SECTION II . Solution of Spherical Right Triangles , 16 when ...
Page 1
... angle formed by their planes . 3. An isosceles spherical triangle is one which has two of its sides equal . An equilateral spherical triangle is one which has all its sides equal . 4. A spherical right triangle is one which has a right ...
... angle formed by their planes . 3. An isosceles spherical triangle is one which has two of its sides equal . An equilateral spherical triangle is one which has all its sides equal . 4. A spherical right triangle is one which has a right ...
Page 2
Benjamin Peirce. 11 plane trigonometry , attend first to the solution of right triangles . ( 427 ) CHAPTER II . Spherical Right Triangles . SECTION . I. Napier's Rules for the Solution of Spherical Right Triangles . 5. Problem . P To ...
Benjamin Peirce. 11 plane trigonometry , attend first to the solution of right triangles . ( 427 ) CHAPTER II . Spherical Right Triangles . SECTION . I. Napier's Rules for the Solution of Spherical Right Triangles . 5. Problem . P To ...
Page 3
Benjamin Peirce. of the planes BOC and AOC is equal to the angle ( 428 ) C , that is , to a right angle ; these two planes are , therefore , perpendicular to each other . Moreover , the angle BOA , measured by BA , is equal to BA or h ...
Benjamin Peirce. of the planes BOC and AOC is equal to the angle ( 428 ) C , that is , to a right angle ; these two planes are , therefore , perpendicular to each other . Moreover , the angle BOA , measured by BA , is equal to BA or h ...
Page 8
... spherical right triangle ABC ( fig . 2. ) right - angled at C. First . If co . h were made the middle part , then , by ( 473 ) , co . A and co . B would be adjacent parts , and a and b opposite parts ; and , by ( 474 ) and ( 475 ) , we ...
... spherical right triangle ABC ( fig . 2. ) right - angled at C. First . If co . h were made the middle part , then , by ( 473 ) , co . A and co . B would be adjacent parts , and a and b opposite parts ; and , by ( 474 ) and ( 475 ) , we ...
Other editions - View all
First Part of an Elementary Treatise on Spherical Trigonometry (Classic Reprint) Benjamin Peirce No preview available - 2017 |
First Part of an Elementary Treatise on Spherical Trigonometry Benjamin Peirce No preview available - 2016 |
Common terms and phrases
A'BC ABC+ the surface AC the perpendicular adjacent angles angles are given angles respectively equal AP and PC ar.co B'OC Corollary cosec cosine of half cotan Demonstration differs from 90 equal to 90 fall on AC given angle given leg given sides given value greater than 90 h tang half the sum Hence hypothenuse included angle Lemma less from 90 less than 90 Let ABC fig let fall logarithm lunary surface means of 496 middle negative obtuse opposite angle opposite side perpendicular BP perpendicular to OA planes BOC Problem quotient right angle right triangle fig right triangle PBC Scholium second member Secondly side BC sides and angles sides equal Solution of Spherical solve a spherical solve the triangle spherical right triangle spherical triangle ABC SPHERICAL TRIGONOMETRY substituted supplements surface ABC tangent of half Thirdly tive trian triangle ABC figs
Popular passages
Page 69 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. D c A' D' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove AABC = ABxAC. A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.
Page 1 - A spherical triangle is a portion of the surface of a sphere, bounded by three arcs of great circles.
Page 69 - THEOREM. The surface of a spherical triangle is measured by the excess of the sum of its three angles above two right angles, multiplied by the tri-rectangular triangle.
Page 8 - I. The sine of the middle part is equal to the product of the tangents of the adjacent parts.
Page 8 - II. The sine of the middle part is equal to the product of the cosines of the opposite parts.
Page 30 - Any angle is greater than the difference between 180° and the sum of the other two angles.
Page 51 - The cosine of half the sum of two sides of a spherical triangle is to the cosine of half their difference as the cotangent of half the included angle is to the tangent of half the sum of the other two angles.
Page 51 - The cosine of half the sum of two angles of a spherical triangle is to the cosine of half their difference as the tangent of half the included side is to the tangent of half the sum of the other two sides.
Page 71 - ... and the sum of the angles in all the triangles is evidently the same as that of all the angles of the polygon ; hence, the surface of the polygon is equal to the sum of all its angles, diminished by twice as many right angles as it has sides less two, into the tri-rectangular triangle.
Bibliographic information
| Title | First Part of an Elementary Treatise on Spherical Trigonometry |
| Author | Benjamin Peirce |
| Publisher | J. Munroe, 1836 |
| Original from | the University of Michigan |
| Digitized | 11 Jun 2007 |
| Length | 71 pages |
| Export Citation | BiBTeX EndNote RefMan |