A Treatise of Plane and Spherical Trigonometry: In Theory and Practice ; Adapted to the Use of Students ; Extracted Mostly from Similar Works of Ludlam, Playfair, Vince, and Bonnycastle |
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Page 12
... secant of the angle at the base CAB . This is manifest from the definitions . PROP . I. 49. In any right - angled plane triangle , the hypothe- nuse is to either of the sides , as the radius to the sine of the angle opposite to that ...
... secant of the angle at the base CAB . This is manifest from the definitions . PROP . I. 49. In any right - angled plane triangle , the hypothe- nuse is to either of the sides , as the radius to the sine of the angle opposite to that ...
Page 22
... secant . For AB : AC :: R : sec . A , therefore R : sec . A :: AB : AC . In the third case , when the hypothenuse AC and the side BC are given , to find AB , a solution may be obtained from 47. 1. For AB - AC2 - BC , therefore AB = AC2 ...
... secant . For AB : AC :: R : sec . A , therefore R : sec . A :: AB : AC . In the third case , when the hypothenuse AC and the side BC are given , to find AB , a solution may be obtained from 47. 1. For AB - AC2 - BC , therefore AB = AC2 ...
Page 32
... secants ( 29 ) . Ex . 2. Given the hypothenuse AC 121 yards , and the angle at the base A 55 ° 30 ' , to find the rest . Answer . BC = 99-719 yards , AB = 68-535 , angle C = 34 ° 30 ′ . Case 2. Given the side AB 125 , and the angle A 51 ...
... secants ( 29 ) . Ex . 2. Given the hypothenuse AC 121 yards , and the angle at the base A 55 ° 30 ' , to find the rest . Answer . BC = 99-719 yards , AB = 68-535 , angle C = 34 ° 30 ′ . Case 2. Given the side AB 125 , and the angle A 51 ...
Page 33
... Secants . * 1 : 1 · 2489484 :: 125 : BC = 156-11855 . 1 : 1 · 5964824 :: 125 : AC = 199.5603 . Solution by Logarithmic Sines , Tangents , and Secants . Log . BC = log . tan . A + log . AB - log . R. Log . tan . 51 ° 19 ′ Log . AB 125 ...
... Secants . * 1 : 1 · 2489484 :: 125 : BC = 156-11855 . 1 : 1 · 5964824 :: 125 : AC = 199.5603 . Solution by Logarithmic Sines , Tangents , and Secants . Log . BC = log . tan . A + log . AB - log . R. Log . tan . 51 ° 19 ′ Log . AB 125 ...
Page 34
... secants . That extent will reach from 125 to 199.5 on the numbers , and will be the length of AC . Ex . 2. Given the base AB 50 , and the angle at the base A 25 ° 17 ' , to find the rest . Answer . Angle C = 64 ° 43 ′ , BC = 23 · 617 ...
... secants . That extent will reach from 125 to 199.5 on the numbers , and will be the length of AC . Ex . 2. Given the base AB 50 , and the angle at the base A 25 ° 17 ' , to find the rest . Answer . Angle C = 64 ° 43 ′ , BC = 23 · 617 ...
Common terms and phrases
90 degrees adjacent angle AHDL algebra analogy angle ABC angle ACB Answer arc AC arc or angle base centre chord circle comp complement cosecant cosine cotangent Euclid's Elements find the angles find the rest formulę geometry Given the side greater than 90 half the sum half their difference height Hence hypothenuse AC included angle less than 90 logarithmic sines mathematics measured mechanical philosophy negative opposite angle perp perpendicular plane triangle plane trigonometry PROP propositions quadrant AH quantity right-angled spherical triangle right-angled triangle Scholium secant side AB side AC sides and angles sine a sine sine and cosine sines and tangents solution spherical angle spherical triangle ABC spherical trigonometry supplement tables tangent of half theorems third side three angles three sides triangle are given trigono versed sine yards
Popular passages
Page 12 - In every plane triangle, the sum of two sides is to their difference as the tangent of half the sum of the angles opposite those sides is to the tangent of half their difference.
Page ix - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds.
Page 23 - Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer.
Page 13 - In any triangle, twice the rectangle contained by any two sides is to the difference between the sum of the squares of those sides, and the square of the base, as the radius to the cosine of the angle included by the two sides. Let ABC be any triangle, 2AB.BC is to the difference between AB2+BC2 and AC2 as radius to cos.
Page 87 - The cosine of half the sum of two sides of a spherical triangle is to the cosine of half their difference as the cotangent of half the included angle is to the tangent of half the sum of the other two angles. The sine of half the sum of two sides of a spherical...
Page 74 - The sum of any two sides is greater than the third side, and their difference is less than the third side.