Robinson's New Practical Arithmetic for Common Schools and Academies |
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Page 352
... root . The law governing this relation is exhibited in the following : Roots . 1 9 99 999 Squares . Roots . Squares . 1 1 1 81 10 1,00 98,01 100 1,00,00 99,80,01 1000 1,00,00,00 From these examples we perceive 1. That a root consisting ...
... root . The law governing this relation is exhibited in the following : Roots . 1 9 99 999 Squares . Roots . Squares . 1 1 1 81 10 1,00 98,01 100 1,00,00 99,80,01 1000 1,00,00,00 From these examples we perceive 1. That a root consisting ...
Page 354
... root being tenths , its square will be hundredths . The trial divisor to obtain the width of this new enlargement , or the next figure in the root , will be , for the same reason as before , twice 73 , the root already found , with one ...
... root being tenths , its square will be hundredths . The trial divisor to obtain the width of this new enlargement , or the next figure in the root , will be , for the same reason as before , twice 73 , the root already found , with one ...
Page 355
... root for the first figure in the root ; subtract the square number from the left - hand period , and to the remainder bring down the next period for a dividend . III . At the left of the dividend write twice the first figure of the root ...
... root for the first figure in the root ; subtract the square number from the left - hand period , and to the remainder bring down the next period for a dividend . III . At the left of the dividend write twice the first figure of the root ...
Page 357
... root of the sum of the squares of the other two sides . III . The areas of two circles are to each other as the ... root of the difference of the hypotenuse and that of the other side . V. The ratio of the area of two similar figures ...
... root of the sum of the squares of the other two sides . III . The areas of two circles are to each other as the ... root of the difference of the hypotenuse and that of the other side . V. The ratio of the area of two similar figures ...
Page 358
... root , and obtain 5 feet , the hypotenuse . 2. A circular skating rink has a diameter of 75 feet . What would be the diameter of a similar rink with the area ? Ans . 43.3 feet . 3. If an army of 55225 men is drawn up in the form of a ...
... root , and obtain 5 feet , the hypotenuse . 2. A circular skating rink has a diameter of 75 feet . What would be the diameter of a similar rink with the area ? Ans . 43.3 feet . 3. If an army of 55225 men is drawn up in the form of a ...
Other editions - View all
Robinson's New Practical Arithmetic for Common Schools and Academies Horatio Nelson Robinson No preview available - 2009 |
Robinson's New Practical Arithmetic for Common Schools and Academies Horatio Nelson Robinson No preview available - 2016 |
Common terms and phrases
acres altitude annex annuity barrels of flour base bill bought bushels ciphers circumference column common denominator common difference common fraction compound interest contained cords cube root cubic decimal point diameter discount dividend division dollars dry measure equal exact divisor EXAMPLES expressed feet figure Find the cost gain gallons geometrical progression given number greatest common divisor Hence hogshead hundred improper fraction inches integers invested least common multiple longitude lower denominations measure merchant miles minuend mixed number months multiplicand Multiply number of terms obtain OPERATION paid payment pounds premium prime factors principal proper fraction quotient rate per cent ratio Reduce remainder result rods RULE RULE.-I sells side sold SOLUTION square root subtract subtrahend tens third thousand thousandths trial divisor triangle units wheat whole number wide worth write
Popular passages
Page 178 - LIQUID MEASURE 4 gills (gi.) = 1 pint (pt.) 2 pints = 1 quart (qt...
Page 171 - Square Measure 144 square inches (sq. in.) = 1 square foot (sq. ft.) 9 square feet = 1 square yard (sq. yd.) 30j square yards = 1 square rod (sq. rd.) 160 square rods = 1 acre (A.) 640 acres = 1 square mile (sq.
Page 184 - A circle is a plane figure bounded by a curved line, called the circumference, every point of which is equally distant from a point within called the center.
Page 306 - Multiply each payment by its term of credit, and divide the sum of the products by the sum of the payments ; the quotient will be the average term of credit.
Page 178 - DRY MEASURE 2 pints (pt.) = 1 quart (qt.) 8 quarts =1 peck (pk.) 4 pecks = 1 bushel (bu...
Page 183 - Thirty days hath September, April, June, and November ; All the rest have thirty-one, Except the second month alone, Which has but twenty-eight, in fine, Till leap year gives it twenty-nine.
Page 396 - A Cylinder is a body bounded by a uniformly curved surface, its ends being equal and parallel circles.
Page 298 - Thirty days after sight of this first of exchange (second and third of the same tenor and date unpaid...
Page 134 - RULE. Divide as in whole numbers, and from the right hand of the quotient point off as many places for decimals as the decimal places in the dividend exceed those in the divisor.
Page 75 - Divide the product of the remaining factors of the dividend by the product of the remaining factors of the divisor, and the result will be the quotient.