Elements of Geometry and Trigonometry |
From inside the book
Results 6-10 of 42
Page 57
... pass through two given points ; hence the line DE must itself be that perpendicular , which divides AB into two equal parts at the point C. 8 PROBLEM II . At a given point , in a BOOK III . 57 Problems relating to the First and Third Books,
... pass through two given points ; hence the line DE must itself be that perpendicular , which divides AB into two equal parts at the point C. 8 PROBLEM II . At a given point , in a BOOK III . 57 Problems relating to the First and Third Books,
Page 58
... line AE is a perpendicular passing through the middle of BD ( Book I. Prop . XVI . Cor . ) . PROBLEM IV . At a point in a given line , to make an angle equal to a given angle . Let A be the given point , AB the given 58 GEOMETRY .
... line AE is a perpendicular passing through the middle of BD ( Book I. Prop . XVI . Cor . ) . PROBLEM IV . At a point in a given line , to make an angle equal to a given angle . Let A be the given point , AB the given 58 GEOMETRY .
Page 63
... a circum- E ference pass through three given points A , B , C ; and also for describing a circumference , in which , a given triangle ABC shall be inscribed . PROBLEM XIV . Through a given point , to draw BOOK III . 63.
... a circum- E ference pass through three given points A , B , C ; and also for describing a circumference , in which , a given triangle ABC shall be inscribed . PROBLEM XIV . Through a given point , to draw BOOK III . 63.
Page 64
... passing through the point A : they are equal , because the right angled triangles CBA , CDA , have the hypothenuse ... pass through the centre of the circle . PROBLEM XV . To inscribe a circle in a given triangle . Let ABC be the given ...
... passing through the point A : they are equal , because the right angled triangles CBA , CDA , have the hypothenuse ... pass through the centre of the circle . PROBLEM XV . To inscribe a circle in a given triangle . Let ABC be the given ...
Page 110
... pass through the point D. By the same mode of reasoning , it might be shown , that the circle which passes through the three points B , C , D , will also pass through the point E ; and so of all the rest : hence the circle which passes ...
... pass through the point D. By the same mode of reasoning , it might be shown , that the circle which passes through the three points B , C , D , will also pass through the point E ; and so of all the rest : hence the circle which passes ...
Other editions - View all
Common terms and phrases
adjacent adjacent angles altitude angle ACB angle BAC ar.-comp base multiplied bisect Book centre chord circ circumference circumscribed common cone consequently convex surface cylinder diagonal diameter dicular distance draw drawn equal angles equally distant equation equiangular equivalent figure formed four right angles frustum given angle given line gles greater homologous sides hypothenuse inscribed circle inscribed polygon intersection less Let ABC let fall logarithm measured by half number of sides opposite parallelogram parallelopipedon pendicular perimeter perpen perpendicular plane MN polyedron polygon ABCDE prism proportional PROPOSITION pyramid quadrant quadrilateral quantities radii radius ratio rectangle regular polygon right angled triangle S-ABC Scholium secant secant line segment side BC similar solid angle solid described sphere spherical polygon spherical triangle square described straight line tang tangent THEOREM triangle ABC triangular prism vertex