## Elements of Geometry and Trigonometry |

### From inside the book

Results 1-5 of 31

Page 16

F F If two triangles have two sides and the

F F If two triangles have two sides and the

**included**angle of the one , equal to two sides and the**included**angle of the other , each to each , the two triangles will be equal . Let the side ED be equal to the side BA , the side DF to ... Page 17

If two triangles have two angles and the

If two triangles have two angles and the

**included**side of the one , equal to two angles and the**included**side of the other , each to each , the two triangles will be equal . Let the angle E be equal to the angle B , the angle F to the ... Page 18

If two triangles have two sides of the one equal to two sides of the other , each to each , and the

If two triangles have two sides of the one equal to two sides of the other , each to each , and the

**included**angles unequal , the third sides will be unequal ; and the greater side will belong to the triangle which has the greater ... Page 21

Now , in the two triangles BDC , BAC , we have BD - AC , by construction ; the angle B equal to the angle ACB , by hypothesis ; B and the side BC common : therefore , the two triangles , BDC , BAC , have two sides and the

Now , in the two triangles BDC , BAC , we have BD - AC , by construction ; the angle B equal to the angle ACB , by hypothesis ; B and the side BC common : therefore , the two triangles , BDC , BAC , have two sides and the

**included**angle ... Page 32

Two parallels AB , CD ,

Two parallels AB , CD ,

**included**between two other parallels AD , BC , are equal ; and the diagonal DB divides the parallelogram into two equal triangles . PROPOSITION XXIX . THEOREM . If the opposite sides of a quadrilateral are equal ...### What people are saying - Write a review

We haven't found any reviews in the usual places.

### Other editions - View all

### Common terms and phrases

ABCD adjacent altitude base become Book called centre chord circle circumference circumscribed common cone consequently construction contained corresponding cosine Cotang cylinder described diameter difference distance divided draw drawn equal equation equivalent evident expressed extremities fall figure follows formed formulas four frustum give given gles greater half hence homologous included inscribed intersection less likewise logarithm manner means measured meet middle multiplied opposite parallel parallelogram parallelopipedon pass perpendicular plane polygon prism PROBLEM Prop proportional PROPOSITION pyramid quantities radii radius ratio reason rectangle regular remaining right angles Scholium segment shown sides similar sine solid solid angle sphere spherical triangle square straight line Suppose surface taken tang tangent THEOREM third triangle triangle ABC vertex whole