The Elements of Euclid, the parts read in the University of Cambridge [book 1-6 and parts of book 11,12] with geometrical problems, by J.W. Colenso1846 |
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Page 64
... double of AK : But AK , CE are the gno- mon AKF , together with the square CK ; therefore the gnomon AKF , together with the square CK , is double of AK : But H D K twice the rectangle AB , BC is double of AK , for BK is equal to BC ...
... double of AK : But AK , CE are the gno- mon AKF , together with the square CK ; therefore the gnomon AKF , together with the square CK , is double of AK : But H D K twice the rectangle AB , BC is double of AK , for BK is equal to BC ...
Page 65
... double of the square of half the line and of the square of the line between the points of section . Let the straight line AB be divided at the point C into two equal , and at D into two un- equal parts : the squares of AD , DB shall be ...
... double of the square of half the line and of the square of the line between the points of section . Let the straight line AB be divided at the point C into two equal , and at D into two un- equal parts : the squares of AD , DB shall be ...
Page 66
... double of the square of AC : Again , because EG is equal to GF , the square of EG is equal to the square of GF , and therefore the squares of EG , GF are double of the square of GF : But the square of EF is equal to the squares of EG ...
... double of the square of AC : Again , because EG is equal to GF , the square of EG is equal to the square of GF , and therefore the squares of EG , GF are double of the square of GF : But the square of EF is equal to the squares of EG ...
Page 67
... double of the square of half the line bisected , and of the square of the line made up of the half and the part produced . Let the straight line AB be bisected in C , and pro- duced to D : the squares of AD , DB shall be together double ...
... double of the square of half the line bisected , and of the square of the line made up of the half and the part produced . Let the straight line AB be bisected in C , and pro- duced to D : the squares of AD , DB shall be together double ...
Page 68
... double of the square of AC : But the square of AE is equal to the squares of AC , CE ; there- fore the square of AE is double of the square of AC : Again , because EF is equal to FG , the square of EF is equal to the square of FG , and ...
... double of the square of AC : But the square of AE is equal to the squares of AC , CE ; there- fore the square of AE is double of the square of AC : Again , because EF is equal to FG , the square of EF is equal to the square of FG , and ...
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The Elements of Euclid, the Parts Read in the University of Cambridge [Book ... Euclides No preview available - 2016 |
Common terms and phrases
ABCD adjacent angles angle ABC angle ACB angle BAC angle BCD angle EDF angle equal base BC BC is equal centre chord circle ABC circumference cuts the circle diameter double draw equal angles equal to F equiangular equilateral triangle equimultiples exterior angle fore given circle given line given point given straight line gnomon greater ratio inscribed intersection isosceles triangle less Let ABC Let the straight lines be drawn lines drawn meet multiple opposite angles opposite sides parallel to BC parallelogram pentagon perpendicular plane polygon PROB produced proportionals Q.E.D. PROP rectangle contained rectilineal figure remaining angle right angles right-angled triangle segment semicircle shew shewn square of AC straight line &c straight line AB THEOR touches the circle triangle ABC twice the rectangle Wherefore
Popular passages
Page 42 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Page 4 - Let it be granted that a straight line may be drawn from any one point to any other point.
Page 33 - F, which is the common vertex of the triangles: that is », together with four right angles. Therefore all the angles of the figure, together with four right angles are equal to twice as many right angles as the figure has sides.
Page 62 - If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line.
Page 22 - If from the ends of a side of a triangle, there be drawn two straight lines to a point within the triangle, these shall be less than the other two sides of the triangle, but shall contain a greater angle.
Page 58 - If there be two straight lines, one of which is divided into any number of parts, the rectangle contained by the two straight lines is equal to the rectangles contained by the undivided line, and the several parts of the divided line.
Page 146 - ... may be demonstrated from what has been said of the pentagon : and likewise a circle may be inscribed in a given equilateral and equiangular hexagon, and circumscribed about it, by a method like to that used for the pentagon.
Page 194 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Page 2 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another : 16.
Page 69 - To divide a given straight line into two parts, so that the rectangle contained by the whole, and one of the parts, may be equal to the square of the other part.