## Euclidian Geometry |

### From inside the book

Results 6-10 of 61

Page 20

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**describe**a ✪ cutting BC in D and E. With centres D and E**describe**equal os intersecting in F. Join AF , cutting BC in G. Then shall AG be 1 to BC . Join AD , AE , FD , FE . Then · . · • DA , AF , FD are respectively = EA , AF , FE ... Page 29

... . 18 ) but it is not ; and if the BAC were the △ EDF , then would the base BC be = the base EF , ( 1.4 ) but it is not ; ... the BAC must be the EDF L PROBLEM D.

... . 18 ) but it is not ; and if the BAC were the △ EDF , then would the base BC be = the base EF , ( 1.4 ) but it is not ; ... the BAC must be the EDF L PROBLEM D.

**Describe**a triangle having its sides equal to INEQUALITIES . 29. Page 30

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**describe**a △ having its sides equal to A , B , C respectively . Take a straight line DK unlimited towards K ; cut off DE , EF , FM equal to A , B , C respectively . With E as a centre and radius ED**describe**the circle DGH ; and with F ... Page 31

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**describe**a circle cutting AB , AC in F and G ; and with centre D**describe**an equal circle HKM cutting DE in H. Join FG ; with centre H and radius = FG**describe**a circle cutting the circle HKM in K. Join DK ; then EDK is the Join HK ... Page 50

... AX , and ... AB is divided into five equal parts . ( I. 26 ) In like manner may a straight line be divided into any given number of equal parts . PROBLEM K.

... AX , and ... AB is divided into five equal parts . ( I. 26 ) In like manner may a straight line be divided into any given number of equal parts . PROBLEM K.

**Describe**a square on a given straight line 50 QUADRILATERALS AND MULTILATERALS .### Other editions - View all

### Common terms and phrases

Algebra base Cambridge centre chord circumference cloth Conic Sections Crown 8vo Describe a circle diagonals diameter divided draw a straight ELEMENTARY TREATISE English equiangular equilateral Euclid Extra fcap fcap GEOMETRY given angle given circle given point given straight line Grammar greater H Let Hence inscribed intersecting isosceles triangle Latin Let ABC line bisecting locus Mathematical meet opposite angles Owens College parallel parallelogram perimeter perpendicular plane polygon PROBLEM produced Professor proportional PROPOSITION ratio rect rectangle rectangle contained rectilineal figure regular polygon respectively rhombus right angles Schools Second Edition segment similar Similarly squares on AC straight line drawn straight line joining tangent THEOREM TRIGONOMETRY twice rectangle twice the squares vertex