Elements of Geometry and Trigonometry: From the Works of A.M. Legendre |
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Page 94
... ABCD and EFGH have equal bases and equal altitudes : then will the parallelograms be equal . For , let them be so placed that their lower bases shall coincide ; then , because they have the same altitude , their upper bases will be in ...
... ABCD and EFGH have equal bases and equal altitudes : then will the parallelograms be equal . For , let them be so placed that their lower bases shall coincide ; then , because they have the same altitude , their upper bases will be in ...
Page 96
... ABCD be divi- ded into 7 , and HEFK into 4 rectangles , all of which will be equal , because they have equal bases and equal altitudes ( P. I. ) : hence , we have , ABCD : HEFK :: 7 : 4 . But we have , by hypothesis , AB : HE :: 7 : 4 ...
... ABCD be divi- ded into 7 , and HEFK into 4 rectangles , all of which will be equal , because they have equal bases and equal altitudes ( P. I. ) : hence , we have , ABCD : HEFK :: 7 : 4 . But we have , by hypothesis , AB : HE :: 7 : 4 ...
Page 97
... ABCD , so that it shall take the position AEFD . Then , if the rectangles are not pro- portional to their bases , let us sup- pose that in which ABCD : AEFD :: AB AO AO is greater than AE . A E IOB : A0 ; Divide AB into equal parts ...
... ABCD , so that it shall take the position AEFD . Then , if the rectangles are not pro- portional to their bases , let us sup- pose that in which ABCD : AEFD :: AB AO AO is greater than AE . A E IOB : A0 ; Divide AB into equal parts ...
Page 98
... ABCD and AEGF be two rectangles : then wil ABCD be to AEGF , as AB X AD is to AE × AF . For , place the rectangles so that the angles DAB and EAF shall be opposite or vertical ; then , produce the sides CD and GE till they meet in H ...
... ABCD and AEGF be two rectangles : then wil ABCD be to AEGF , as AB X AD is to AE × AF . For , place the rectangles so that the angles DAB and EAF shall be opposite or vertical ; then , produce the sides CD and GE till they meet in H ...
Page 99
... ABCD be a parallelogram , AB its base , and BE its altitude : then will the area of ABCD be equal to AB × BE . For , construct the rectangle ABEF , having the same base and altitude : then will the rec- tangle be equal to the parallelo ...
... ABCD be a parallelogram , AB its base , and BE its altitude : then will the area of ABCD be equal to AB × BE . For , construct the rectangle ABEF , having the same base and altitude : then will the rec- tangle be equal to the parallelo ...
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Common terms and phrases
AB² ABCD AC² adjacent angles altitude apothem Applying logarithms base and altitude bisect centre chord circle circumference circumscribed coincide cone consequently convex surface corresponding cosec cosine Cotang cylinder denote diagonals diameter difference distance divided draw drawn edges equally distant feet find the area Formula frustum given angle given straight line greater hence homologous hypothenuse included angle interior angles intersection less Let ABC log sin lower base mantissa measured by half number of sides opposite parallel parallelogram parallelopipedon perimeter perpendicular plane MN polyedral angle polyedron prism PROPOSITION proved pyramid quadrant radii radius rectangle regular polygons right angles right-angled triangle Scholium secant segment semi-circumference side BC similar sine slant height sphere spherical polygon spherical triangle square subtracted Tang tangent THEOREM triangle ABC triangular prisms triedral angle upper base vertex vertices whence
Popular passages
Page 126 - The square of the hypothenuse is equal to the sum of the squares of the other two sides ; as, 5033 402+302.
Page 59 - A'B'C', and applying the law of cosines, we have cos a' = cos b' cos c' + sin b' sin c' cos A'. Remembering the relations a' = 180° -A, b' = 180° - B, etc. (this expression becomes cos A = — cos B cos C + sin B sin C cos a.
Page 18 - The circumference of every circle is supposed to be divided into 360 equal parts called degrees, and each degree into 60 equal parts called minutes, and each minute into 60 equal parts called seconds, and these into thirds, fourths, &c.
Page 104 - The square described on the hypothenuse of a rightangled triangle is equal to the sum of the squares described on the other two sides.
Page 6 - The logarithm of any power of a number is equal to the logarithm of the number multiplied by the exponent of the power.
Page 28 - If two triangles have two sides of the one equal to two sides of the...
Page 46 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Page 99 - The area of a parallelogram is equal to the product of its base and altitude.
Page 172 - If two planes are perpendicular to 'each other, a straight line drawn in one of them, perpendicular to their intersection, will be perpendicular to the other.
Page 214 - A sphere is a solid bounded by a curved surface, every point of which is equally distant from a point within called the center.