 | C. Davies - 1867 - 342 pages
...inscribe within the frustum of a cone the frustum of a right pyramidThe convex surface of this frustum is equal to one-half the sum of the perimeters of its bases multiplied by the slant height (B- VITh XV-) ; and this is true whatever the number of lateral faces ; hence, it... | |
 | George Albert Wentworth - Geometry - 1877 - 436 pages
...and p respectively, and its slant height by I. Then s = | (P + p) I, § 570 (the lateral area of the frustum of a regular pyramid is equal to one-half...the sum of the perimeters of its bases multiplied by the slant Iieight). Now, let the number of lateral faces be indefinitely increased, the new elements... | |
 | George Albert Wentworth - Geometry - 1877 - 416 pages
...and p respectively, and its slant height by I. Then » = $(P + p)l, § 570 (Ihe lateral area of the frustum of a regular pyramid is. equal to one-half the sum of the perimeters of us bases multiplied by the slant height). CONES. Then P, p, and /, approach. C, с, ала L, respectively... | |
 | George Albert Wentworth - Geometry - 1877 - 426 pages
...respectively, and its slant height by l. Then s = | (P + p) t, § 570 (the lateral area of the fnatnm of a regular pyramid is equal to one-half the sum of the perimeters of us bases multiplied bi' the slant height). Now, let the number of lateral faces be indefinitely increased,... | |
 | William Henry Harrison Phillips - Geometry - 1878 - 236 pages
...frustum of that pyramid cut off by a plane 3 feet from the base. XVI. Theorem. The lateral surface of .a frustum of a regular pyramid is equal to one-half...perimeters of its bases multiplied by its slant height. For the faces of a frustum of a regular pyramid are equal trapezoids, and each is measured by one-half... | |
 | F. B. Stevens - Examinations - 1884 - 202 pages
...circumferences. 5. The sum of any two face angles of a triedral angle is greater than the third. G. The lateral area of a frustum of a regular pyramid is equal to its slant height into half the sum of the perimeters of its bases. 7. Write expressions for the volume... | |
 | Webster Wells - Geometry - 1886 - 392 pages
...§ 827, lateral area 0-ABCDE = AB x ^OH + BC x $OH+ etc. = (AB + BC + etc.) x \OH. 563. COROLLARY-. The lateral area of a frustum of a regular pyramid...perimeters of its bases multiplied by its slant height. For the lateral area of the frustum Ad is the sum of the areas of the trapezoids Ab, Be, etc., whose... | |
 | Webster Wells - Geometry - 1886 - 166 pages
...sum of its parallel sides multiplied by its altitude (§ 331). Hence the lateral area of the frustum is equal to one-half the sum of the perimeters of its bases multiplied by its slant height. • PROPOSITION XIX. THEOREM. 564. A triangular pyramid is equivalent to one-third of a triangular... | |
 | George Albert Wentworth - Geometry - 1888 - 466 pages
...the lateral area of the pyramid. .-. S=$VH(AB+ BC+etc.). ae.D. 597. COR. 1. The lateral area of the frustum of a regular pyramid, is equal to one-half the sum of the perimeters of the bases multiplied by the slant height of the frustum. § 371 PROPOSITION XV. THEOREM. 598. // a... | |
 | Yale University - 1892 - 200 pages
...their circumferences. 5. The sum of any two face angles of a triedral angle is greater than the third. 6. The lateral area of a frustum of a regular pyramid is equal to its slant height into half the sum of the perimeters of its bases. 7. Write expressions for the volume... | |
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COR. The lateral area of a frustum of a regular pyramid is equal to one-half the sum of the perimeters of the bases multiplied by the slant height. 
