| Thomas Leybourn - Mathematics - 1814 - 420 pages
...Hence, by adopting the notation in the question, we have But the sum of the angles of any polygon being equal to twice as many right angles as the polygon has sides, less four; the sum of all the angles of the polygon will be equal to an even number of right angles,... | |
| Thomas Leybourn - Mathematics - 1817 - 454 pages
...number of sides. The same by Mr. WD Suookc, WoollJridge, near IVareham. • In any rectilineal figure, the sum of all the interior angles is equal to twice as many right angles, wanting 4, as the figure has sides : therefore let x = the number of sides ; then the sum of all the... | |
| John Radford Young - Euclid's Elements - 1827 - 228 pages
...to say, the sum of the angles of the polygon, together with those about the point within . it, are equal to twice as many right angles as the polygon has sides ; but those angles which are' about the point, amount to four right angles, (Prop. VI. Cor. 2.) deducting... | |
| James Hayward - Geometry - 1829 - 218 pages
...polygon, the sum of the interior and exterior angles is equal to two right angles ( 13) ; consequently the sum of all the interior and exterior angles is equal to as many times two right angles as the polygon has sides. But the sum of all the exterior angles is... | |
| Nathan Scholfield - 1845 - 894 pages
...angles as the figure has sides, wanting four right angles. Hence, the interior angles plus four right angles, is equal to twice as many right angles as the polygon has sides, and consequently, equal to the sum of the interior angles plus the exterior angles. Taking from each... | |
| William Scott - Measurement - 1845 - 288 pages
...end ought to coincide. Also, the sum of all the angles, together with four right angles, ought to be equal to twice as many right angles as the polygon has sides (Eue. i. 32. cor.). To find the angle contained by two straight lines conceived to be drawn from a... | |
| Sir J. Butler Williams - Geodesy - 1846 - 368 pages
...of all the interior angles of the polygon formed by joining the stations by straight lines will be equal to twice as many right angles as the polygon has sides, wanting 4 right angles (Euc. Cor. 32, I.) Thus, if the figure have 3 sides, the sum of the interior... | |
| George Roberts Perkins - Geometry - 1847 - 326 pages
...two right angles (Prop. i) ; •therefore the sum of all the interior angles, together with all the exterior angles, is equal to twice as many right angles as the polygon has sides ; but the sum of all the exterior angles is equal to four right angles (Prop. xxm) ; therefore the... | |
| Charles Davies - Trigonometry - 1849 - 372 pages
...there are as many exterior as interior angles, and as many of each as there are sides of the polygon : hence, the sum of all the interior and exterior angles...angles as the polygon has sides. Again, the sum of all tho interior angles is equal to two right angles, taken as many times, less two, as the polygon has... | |
| Elias Loomis - Conic sections - 1849 - 252 pages
...together with its adjacent exterior angle, ABD, is equal to two right angles (Prop. II.) ; therefore the sum of all the interior and exterior angles, is equal to .y twice as many right angles as the polygon has sides ; that is, they are equal to all the interior... | |
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