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" For the surface of a segment or frustum, multiply the whole circumference of the sphere by the height of the part required. "
The artillerist's manual, and compendium of infantry exercise - Page 325
by Frederick Augustus Griffiths - 1859
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The Young Geometrician's Companion: Being A New and Comprehensive ..., Volume 6

Richard Turner - Geometry - 1787 - 264 pages
...16=208 X4=832X .5236—435.6352 Inches, the Solidity required. For the Curved or Superficial Content, multiply the whole Circumference of the Sphere by the Height of the Segment, and the Product will be the Content required. The Diameter and Circumference of the Sphere...
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A Course of Mathematics in Two Volumes for the Use of Academies as Well as ...

Charles Hutton - Mathematics - 1807 - 464 pages
...decimal '3188, Or divide it by 3'1416, for the surface. Note. For the surface of a segment or frustum, multiply the whole circumference of the sphere by the height of the part required. , Ex. 1 . Required the convex superficies of a sphere, whose diameter is 7, and circumference...
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A Course of Mathematics: In Three Volumes : Composed for the Use of the ...

Charles Hutton - Mathematics - 1811 - 494 pages
...decimal '3183, or divide it by 3-1416, for the surface. Note. For the surface of a segment or frustum, multiply the whole circumference of the sphere by the height of the part required. EX. I . Required the convex superficies of a sphere, whose diameter is 7, and circumference...
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A Course of Mathematics: For the Use of Academies, as Well as Private ...

Charles Hutton - Mathematics - 1822 - 616 pages
...decimal -3183, or divide it by -V1416, for the surface. Nate. For the surface of a segment or frustum, multiply the whole circumference of the sphere by the height of the part required. Ex. 1. Required the convex superficies of a sphere, whose diameter is 7. and circumference...
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An Encyclopędia of Architecture: Historical, Theoretical, and Practical

Joseph Gwilt - Architects - 1842 - 1114 pages
...decimal •3183, or divide it by 3-1416 for the surface. Remark. For the surface of a segment or frustum, multiply the whole circumference of the sphere by the height of the part required. Examplel. Required the convex superficies of a sphere whose diameter is 7 and circumference...
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The Artillerists̓ Manual, and British Soldiers̓ Compendium

Frederick Augustus Griffiths - Artillery - 1859 - 426 pages
...area of the top. As 15 : 6 : : 225 : 90, mean proportional. 24 feet = 288 inches. 225 + 3H + 90X288 To find the surface of a sphere, or any segment. Multiply...whole circumference of the sphere by the height of the pait required, Example. — Required the superficies of a globe whose diameter is 24 inches. 24 X 24...
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