...to subtract — b from a, we add b to a ; or a — (— V) = a + b. Hence, to subtract one quantity from another, change the sign of the subtrahend, and add the result to the minuend. 61. 1. Subtract 5 a from 2 a. By Art. GO, the result is equal to the sum of — 5 a and 2 a, which...

...to subtract — b from a, we add b to a ; or a — (— 6) = a + b. Hence, to subtract one quantity from another, change the sign of the subtrahend, and add the result to the minuend. 61. 1. Subtract 5 a from 2 a. By Art. 60, the result is equal to the sum of — 5a and 2 a, which is...

...39, b + ( — b) = 0. Whence, a— 6 = a + (— 6). Hence, to subtract one number from another, we change the sign of the subtrahend, and add the result to the minuend. I 43. Since Subtraction is only a form of Addition (Art. 42), it follows from Art. 40 that if equal...

...negative number is equivalent to adding an equal positive number. Hence, to subtract one algebraic number from another : Change the sign of the subtrahend, and add the subtrahend to the minuend. This rule is consistent with the definition of subtraction given in § 26...

...b) - a + 6. - 6 - (+ a) = - a - 6 J ^ - 6 + (-a)=-a-6. Hence, in general, To Subtract one Algebraic Number from another. Change the sign of the subtrahend, and add the result to the minuend. Notes : 1. Algebraic subtraction considered as an operation is not distinct from addition ; for it...

...-7 a. + o- {- Ъ)=+а + Ъ ( or' ) + ч + (fb) = e+ 6. Hence, in general, To Subtract one Algebraic Number from another. Change the sign of the subtrahend, and add the result to the minuend. Notes: 1. Algebraic subtraction considered as an operation is not distinct from addition ; for it is...

...subtracting a negative number is equivalent to adding an equal positive number. To Subtract One Algebraic Number from Another, Change the sign of the subtrahend, and add the subtrahend to the minuend. 68. Examples. 1. Find the sum of 3 a, 2 a, a, 5 a, 7 a. The sum of the coefficients...

...shall equal a. Now if a + b be added to — b, the result is a. Hence, the required remainder is а + b. That is, a — ( — b) = a + b. 38. From §§36...— 5 a, and add the result to the minuend. Thus, 2а -бa — 3a, Ans. 2. Subtract — 5 a from — 2 a. The student should perform mentally the operation...

...be added to — b, the result is a. Hence, the required remainder is a + b. That is, a — (—ti) = a + b. 38. From §§36 and 37, we have the following...— 5 a, and add the result to the minuend. Thus, 2a -5a 2. Subtract — 5 a from — 2 a. The student should perform mentally the operation of changing...

...added to — 6, the result is a. Hence, the required remainder is a + b. That is, а — (-6) = а + 6. 38. From §§36 and 37, we have the following rule:...— 5 a, and add the result to the minuend. Thus, 2 а -5а — За, Ans, 2. Subtract — 5 a from —2a. The student should perform mentally the operation...