 | Charles Hutton - Mathematics - 1807 - 464 pages
...by the decimal '5236, for the content. RULE II. To 3 times the square of the radius of the segment's base, add the square of its height ; then multiply the sum by the height, and the product by '5236, for the content. . Ex. 1. To find the content of a spherical segment, of 2 feet in height, cut from... | |
 | Charles Hutton - Mathematics - 1811 - 442 pages
...by the decimal '5236, for the content. RULE II. To 3 times the square of the radius of the segment's base, add the square of its height; then multiply the sum by the height, and the product by -5236, for the content. Ex. 1. To find the content of a spherical segment, of 2 feet in height, cut from a... | |
 | Charles Hutton - Mathematics - 1812 - 620 pages
...-5236, for the content. RULE II. To 3 times the square of the radius of the segment's base, add th« square of its height ; then multiply the sum by the height, and the product by -5236, for tl» content. Ex. 1 . To find the content of a spherical segment, of 3 feet in height, cut from... | |
 | Charles Hutton - Astronomy - 1815 - 686 pages
...surface of the segment. For the solid content of a segment, there are_two rules usually given ; viz, 1. To 3 times the square of the radius of its base, add the square of its height ; multiply the sum by the height, and the product by '5236. Or, 2dly, From 3 times the diameter of... | |
 | Charles Hutton - Mathematics - 1816 - 610 pages
...the content. RULE II. To 3 times the square of the radius of the segment's base, add the square ot its height; then multiply the sum by the height, and the product by -5236, for the content. Ex. 1. To find the content of a spherical segment, of 2 feet in height, cut from a... | |
 | Charles Hutton - Arithmetic - 1818 - 646 pages
...by the decimal -5fc36, for the content. RULE H. To 3 times the square of the radius of the segment's base, add the square of its height ; then multiply the sum by the height, and the product by •6£36, for the content. Ex. 1. To find the content of a spherical segment, of 2 feet in height,... | |
 | William Nicholson - Natural history - 1821 - 382 pages
...the segment. For the solid content of a segment there are two rules usually given; vi:. 1. To three times the square of the radius of its base, add the square of its height ; multiply the sum by the height, and the pioduct by .52J6. Or, 2dly, From three times the diameter... | |
 | Charles Hutton - Mathematics - 1822 - 616 pages
...by the decimal -5236, for the content. RULE II. To 3 times the square of the radius of the segment's base, add the square of its height ; then multiply the sum by the height, and the product by -5236, for the content. Ex. 1 . To find the content of a spherical segment, of 2 feet in height, cut from... | |
 | John Nicholson - Machinery - 1825 - 822 pages
...12 144 12 1728 •5236 10368 5184 3456 8640 Prob. 13. To find the Solidity of a Spherical Segment. To 3 times the square of the radius of its base add...then multiply the sum by the height, and the product aeain by -5236. " l _ Ex. Required the contents of a spherical segment, its height AB being 4, and... | |
 | John Nicholson - Machinery - 1825 - 838 pages
...•5236 10368 5184 3456 8640 904-7808 An*r. Prob. 13. To find the Solidity of a Spherical Segment. To 3 times the square of the radius of its base add the sqnare < height ; then multiply the sum by the height, and the product ¡ by -5236. Ex. Required the... | |
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... -5236, for the content. RULE II. To 3 times the square of the radius of the segment's base, add the square of its height ; then multiply the sum by the height, and the product by -5236, for the content. 
