 | Michael Walsh - Arithmetic - 1801 - 268 pages
...figures, and the firil quotient by the other figure, and it will then give the quotient required But as it fometimes happens that there is a remainder...the quotients, and neither of them the true one, it may be found by this RULE. Multiply the firft divifor by the lail remainder, and to the produft add... | |
 | Michael Walsh - Arithmetic - 1816 - 288 pages
...quotient by the other figure, and ¡twill then give the quotient required. — But as it sometimes happens that there is a remainder to each of the quotients, and seither of them the true one, it may be found by this RULE. Multiply the first divisor by the last... | |
 | Martin Ruter - Arithmetic - 1828 - 180 pages
...quotient thence arising, by the other figure, and it will give the quotient required. As it sometimes happens that there is a remainder to each of the quotients, and neither of them the true one, it may he found thus: — Multiply the first divisor by the last remainder, and to the product add 'the... | |
 | William Kinne - 1829 - 246 pages
...4)7621460 6)4792161 4)1905365 8) —3 Quo. 476341—4 Rem. 99836—5x6+3=33 NOTE.?— 1t sometimes happens that there is a remainder to each of the quotients, and neither of them the true one, but the true remainder may be found by the following rule. RULE.— Multiply the last remainder by... | |
 | Michael Walsh - 1831 - 348 pages
...quotient by the other figure, and it will then give the quotient required. — But as it sometimes happens that there is a remainder to each of the quotients, and neither of them the true one, it may be found by this RULE. Multiply the first divisor by the last remainder, and to the product add... | |
 | Francis Walkingame - 1832 - 224 pages
...those Figures, and that Quotient by the other, it will give the Quotient required. But as it sometimes happens that there is a Remainder to each of the Quotients, and neither of them the true one, it may be found by this RULE. Multiply the first Divisor into the last Remainder, to that Productadd the... | |
 | Michael Walsh - Arithmetic - 1838 - 346 pages
...quotient by the other figure, and it will then give the quotient required. — But as it sometimes happens that there is a remainder to each of the quotients, and neither of them the true one, it may be found by this i RULE. Multiply the first divisor by the last remainder, and to the product add... | |
 | Jason M. Mahan - Arithmetic - 1839 - 312 pages
...9)71589743 10)19762754 11)21796871 12)32719654 12)71962715 give the quotient required. But as it sometimes happens that there is a remainder to each of the quotients, and neither of them the true one, therefore, to find the true remainder, multiply the first divisor by the last remainder ; to that product... | |
 | Francis Walkingame - 1855 - 186 pages
...those figures, and that quotient by the other, it will give the quotient required ; but as it sometimes happens that there is a remainder to each of the quotients, and neither of them the true one, it may be found by this RDLE. Multiply the first divisor into the second remainder, to that product add... | |
 | Francis Walkingame - 1865 - 222 pages
...those figures, and that quotient by the other, it will give the quotient required. But as it sometimes happens that there is a remainder to each of the quotients, and neither of them the true one, it may be found by this EULE. — Multiply the first divisor into the last remainder, to that product... | |
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... give the quotient required. — But as it sometimes happens that there is a remainder to each of the quotients, and neither of them the true one, it may be found by this RULE. Multiply the first divisor by the last remainder, and to the product add... 