Euclid's Elements [book 1-6] with corrections, by J.R. Young1838 |
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Page 95
... arc , that is , upon the same part of the circumference . Let ABC be a circle , and BEC an angle at the centre , and BAC an angle at the circumference , which have the same arc BC for their base : the angle BEC shall be double of the ...
... arc , that is , upon the same part of the circumference . Let ABC be a circle , and BEC an angle at the centre , and BAC an angle at the circumference , which have the same arc BC for their base : the angle BEC shall be double of the ...
Page 97
... arc BC as the angle BAC at the circumference , BFC is the double of BAC . † Again , because 120. 3. the angle BFC at the centre is upon the same arc BC as the angle BEC at the circumference , BFC is the double of BEC ; but it was shown ...
... arc BC as the angle BAC at the circumference , BFC is the double of BAC . † Again , because 120. 3. the angle BFC at the centre is upon the same arc BC as the angle BEC at the circumference , BFC is the double of BEC ; but it was shown ...
Page 99
... arcs , " as is evident from the demonstration . PROP . XXV ... arc . Let ABK be the given arc of a circle ; it is required to describe the circle of which it is the arc . Take any point B in the arc , from which draw any two chords BC ...
... arcs , " as is evident from the demonstration . PROP . XXV ... arc . Let ABK be the given arc of a circle ; it is required to describe the circle of which it is the arc . Take any point B in the arc , from which draw any two chords BC ...
Page 100
... BC , BD , respectively . These perpendiculars will intersect in a point P , which will be the centre of the circle . For the centre of the circle to which * Cor . 1. 3 . the arc BC belongs is in the line B H D K bisecting its chord at ...
... BC , BD , respectively . These perpendiculars will intersect in a point P , which will be the centre of the circle . For the centre of the circle to which * Cor . 1. 3 . the arc BC belongs is in the line B H D K bisecting its chord at ...
Page 101
... arc BKC to the arc ELF . Next let the angles BAC , EDF at the circumferences be equal . Find the centres G and H , and draw GB , GC , BC ; HE , HF , EF ; then , if BAC be less than a right angle , the angle BGC at the centre will stand ...
... arc BKC to the arc ELF . Next let the angles BAC , EDF at the circumferences be equal . Find the centres G and H , and draw GB , GC , BC ; HE , HF , EF ; then , if BAC be less than a right angle , the angle BGC at the centre will stand ...
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Common terms and phrases
ABCD adjacent angles alternate angles angle ABC angle ACB angle BAC angle BCD angle EDF angles equal antecedent arc BC base BC BC is equal bisected centre circle ABC circumference consequent Const demonstrated described diameter double draw equal angles equal to AC equiangular equilateral and equiangular equimultiples Euclid exterior angle fore Geometry given circle given straight line gnomon greater inscribed join less Let ABC Let the straight logarithm multiple opposite angle parallel parallelogram pentagon perpendicular PROB proportion proposition Q. E. D. PROP radius rectangle contained rectilineal figure remaining angle segment side BC similar sine square of AC straight line AB straight line AC tangent THEOR touches the circle triangle ABC triangle DEF twice the rectangle wherefore
Popular passages
Page 30 - IF two triangles have two sides of the one equal to two sides of the other, each to each, but the angle contained by the two sides of one of them greater than the angle contained by the two sides equal to them, of the other ; the base of that which has the greater angle shall be greater than the base of the other.
Page 105 - The angle in a semicircle is a right angle; the angle in a segment greater than a semicircle is less than a right angle; and the angle in a segment less than a semicircle is greater than a right angle.
Page 50 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Page 61 - If a straight line be divided into two equal parts, and also into two unequal parts ; the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line.
Page 65 - If a straight line be divided into any two parts, four times the rectangle contained by the whole line and one of the parts, together with the square of the other part, is equal to the square of the straight line which is made up of the whole and that part.
Page 70 - To divide a given straight line into two parts, so that the rectangle contained by the whole, and one of the parts, may be equal to the square of the other part.
Page 41 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Page 172 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Page 45 - TRIANGLES upon the same base, and between the same parallels, are equal to one another.
Page 38 - If a, straight line fall upon two parallel straight lines, it makes the alternate angles equal to one another; and the exterior angle equal to the interior and opposite upon the same side; and likewise the two interior angles upon the same side together equal to two right angles.