## Elements of Geometry |

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Page vi

The second section , entitled the circle , treats of the most simple properties of the circle , and those of chords , of

The second section , entitled the circle , treats of the most simple properties of the circle , and those of chords , of

**tangents**, and of the measure of angles by the arcs of a circle . These two sections are followed by the resolution ... Page 25

A

A

**tangent**is a line , which has only one point in common with the circumference , as CD . The common point M is called the point of contact . Also two circumferences are**tangents**to each other ( fig . 59 , 60 ) , Fig.69 . when they have ... Page 29

54 . radius AC , is a

54 . radius AC , is a

**tangent**to the circumference . Demonstration . Since every oblique line CE is greater than the perpendicular CA ( 52 ) , the point E is without the circle , and the line BD has only the point A in common with the ... Page 30

56 ) , one be a secant and the other a

56 ) , one be a secant and the other a

**tangent**, to the point of contact H draw the radius CH ; this radius will be perpendicular to the**tangent**DE ( 110 ) , and also to its parallel MP . But , since CH is perpendicular to the chord MP ... Page 31

And if , through the point A , we draw AE perpendicular to CD , the straight line AE will be a

And if , through the point A , we draw AE perpendicular to CD , the straight line AE will be a

**tangent**common to all these circles . a THEOREM .### What people are saying - Write a review

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### Common terms and phrases

ABC fig ABCD adjacent altitude applied base called centre chord circ circle circumference circumscribed common cone consequently construction contained convex surface Corollary cylinder Demonstration described diameter difference distance divided draw drawn entire equal equivalent example extremities faces feet figure follows formed four give given greater half hence inclination inscribed intersection isosceles join less let fall manner mean measure meet moreover multiplied namely opposite parallel parallelogram parallelopiped pass perimeter perpendicular plane plane angles polyedron polygon prism PROBLEM produced proportional proposition pyramid radii radius ratio reason rectangle regular polygon respect right angles Scholium sector segment similar solid angle Solution sphere spherical square straight line suppose surface taken tangent THEOREM third triangle ABC vertex vertices whence