Elements of Geometry |
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Page x
... square , of this number ; 5 × 5 , or 25 , is the second power or square of 5 . The second power , therefore , is the product of two equal fac- tors ; each of these factors is the square root of the product ; 5 is the square root of 25 ...
... square , of this number ; 5 × 5 , or 25 , is the second power or square of 5 . The second power , therefore , is the product of two equal fac- tors ; each of these factors is the square root of the product ; 5 is the square root of 25 ...
Page 2
... square ( fig . 11 ) , which has its sides equal , and its angles right angles , ( See art . 80 ) ; The rectangle ( fig . 12 ) , which has its angles right angles , with- out having its sides equal ( See art . above referred to ) ; The ...
... square ( fig . 11 ) , which has its sides equal , and its angles right angles , ( See art . 80 ) ; The rectangle ( fig . 12 ) , which has its angles right angles , with- out having its sides equal ( See art . above referred to ) ; The ...
Page 16
... square and rectangle ( 17 ) . 66. Corollary II . The sum of the angles of a pentagon is equal to two right angles multiplied by 5-2 , which makes 6 right angles ; therefore , when a pentagon is equiangular , each angle is equal to a ...
... square and rectangle ( 17 ) . 66. Corollary II . The sum of the angles of a pentagon is equal to two right angles multiplied by 5-2 , which makes 6 right angles ; therefore , when a pentagon is equiangular , each angle is equal to a ...
Page 40
... 148. Corollary . If the given angle be a right angle , the figure will be a rectangle ; and , if the adjacent sides are also equal , the figure will be a square . PROBLEM . 149. To find the centre of a given 40 Elements of Geometry .
... 148. Corollary . If the given angle be a right angle , the figure will be a rectangle ; and , if the adjacent sides are also equal , the figure will be a square . PROBLEM . 149. To find the centre of a given 40 Elements of Geometry .
Page 43
... square . But , although the exact ratio cannot be found in numbers , by neglecting the last remainder we may find an approximate ratio to a greater or less degree of exactness , according as the operation is Problems . 43.
... square . But , although the exact ratio cannot be found in numbers , by neglecting the last remainder we may find an approximate ratio to a greater or less degree of exactness , according as the operation is Problems . 43.
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Common terms and phrases
ABC fig adjacent angles altitude angle ACB angle BAC base ABCD bisect centre chord circ circular sector circumference circumscribed common cone consequently construction convex surface Corollary cube cylinder Demonstration diagonals diameter draw drawn equal angles equiangular equilateral equivalent faces figure formed four right angles frustum GEOM given point gles greater hence homologous sides hypothenuse inclination intersection isosceles triangle JOHN CRERAR LIBRARY join less Let ABC let fall line AC mean proportional measure the half meet multiplied number of sides oblique lines opposite parallelogram parallelopiped perimeter perpendicular plane MN polyedron prism produced proposition radii radius ratio rectangle regular polygon right angles Scholium sector segment semicircle semicircumference side BC similar solid angle sphere spherical polygons spherical triangle square described straight line tangent THEOREM three angles triangle ABC triangular prism triangular pyramids vertex vertices whence